Answer:
1083.6 g
Explanation:
At STP, 1 mol of any given mass will occupy 22.4 L.
With the information above in mind we can<u> calculate how many moles of nitrogen gas (N₂) are there in 867 L</u>:
- 867 L ÷ 22.4 L/mol = 38.7 mol
Finally we convert 38.7 moles of N₂ into grams, using its molar mass:
- 38.7 mol * 28 g/mol = 1083.6 g
Answer:
I'm not really sure how to answer it but this is the best I can do:
If the capacity of a mass is 1350 and heat is transferred to increase the temperature by 15. degrees Celcius then the amount of heat that needs to be transferred would be about 45 degrees.
Explanation:
I'm sorry if it's wrong or not exactly the way it's supposed to be answered, I'm not very good with math and temperature problems. But i hope it helps! :)
Answer:
27.99 dm³
Explanation:
Applying
PV = nRT................ Equation 1
Where P = Pressure, V = Volume, n = number of mole, R = molar gas constant, T = Temperature.
From the question, we were aksed to find V.
Therefore we make V the subject of the equation
V = nRT/P................ Equation 2
Given: n = 1.31 moles, T = 37°C = 310K, P = 904 mmHg = (904×0.001316) = 1.1897 atm
Constant: R = 0.082 atm.dm³/K.mol
Substitute these values into equation 2
V = (1.31×310×0.082)/(1.1897)
V = 27.99 dm³