All categories

3 years ago

Please help me I really need it

Physics

1 answer:

tensa zangetsu [6.8K]3 years ago

4 0

Answer:

A 1.5 metres per second squared B 0 C 6 0.5

b) 9m

Explanation:

a= v-a/t

a= acceleration measured in metres per second squared

v= final speed measured in metres per second

u= initial speed measured in metres per second

t= time measured in second

a=v-a/t

a= 3-0/2

a= 1.5 metres per second squared

Distance in a velocity time graph = area under

To calculate the distance in the first 4 seconds

You divide the graph into triangles and rectangles

Area A (triangle )= 1/2 × base × height

=1÷2 ×2×3

= 3m

Area B (rectangle)= L×B

=2×3

=6m

Area A + Area B= 3+6

= 9m

You might be interested in

How are the spiral arms of the milky way detected?

Step2247 [10]

The spiral structure emerges when galactic clusters (open), H II regions and O & B type stars (young stars) are used as tracers. We know this to be true as other pinwheel galaxies exhibit the same patterns across these tracers as in the milky way.

6 0

3 years ago

What change occurs to the mass of an object when an unbalanced force is applied to it

strojnjashka [21]

The mass of an object always stays the same since it is really just the amount of matter in an object so no matter the force applied, as long as the object does not lose or gain matter, the object stays the same

5 0

1 year ago

A projectile enters a resisting medium at x = 0 with an initial velocity v0 = 910 ft/s and travels 5 in. before coming to rest.

evablogger [386]

Answer:

a = - 1.987 × 10⁶ ft/s²

t = 6.84 × 10⁻⁴ s

Explanation:

v₀ = 910 ft/s

x = 5 in.

relation v = v₀ - k x

v = 0 as body comes to rest

0 = 900 - 5k/12

k = 2184 s⁻¹

acceleration

$\frac{\mathrm{d} v}{\mathrm{d} t} = -k\frac{\mathrm{d} x}{\mathrm{d} t}$

where

(A) a = -k × v

at v= 910 ft/s

a = - 1.987 × 10⁶ ft/s²

(B) at x = 3.9 in.

v = 910 - 3.9(2184)/12

v = 200.2 m/s

$\frac{\mathrm{d} v}{\mathrm{d} t} = -k\frac{\mathrm{d} x}{\mathrm{d} t}$

$\frac{dv}{v} = -kdt$

$\int\limits^{200.2}_{900} {\frac{1}{v} }dv = -k\int\limits^t_0 dt$

$ln(200.2)-ln(900) = -kt$

t = 6.84 × 10⁻⁴ s

3 0

2 years ago

Hey people text me at azieyafreeman2 at g mail dot com

butalik [34]

Answer:

Explanation:

or zo0m meet??

8 0

3 years ago

Read 2 more answers

Gravity is a force. Gravity is also an example of __________________. . . A.. a theory. . B.. an established procedure. . C.. a

MissTica

The correct answer to this question is C - Gravity is a force. Gravity is also an example of a universal law. Well, according to Isaac Newton, anyway. According to Newton's Law of Universal Gravitation, 'every point mass attracts every single point mass by a force pointing along the line intersecting both paths.'
<span />

7 0

2 years ago