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3 years ago

Please help me I really need it

Physics

1 answer:

tensa zangetsu [6.8K]3 years ago

4 0

Answer:

A 1.5 metres per second squared B 0 C 6 0.5

b) 9m

Explanation:

a= v-a/t

a= acceleration measured in metres per second squared

v= final speed measured in metres per second

u= initial speed measured in metres per second

t= time measured in second

a=v-a/t

a= 3-0/2

a= 1.5 metres per second squared

Distance in a velocity time graph = area under

To calculate the distance in the first 4 seconds

You divide the graph into triangles and rectangles

Area A (triangle )= 1/2 × base × height

=1÷2 ×2×3

= 3m

Area B (rectangle)= L×B

=2×3

=6m

Area A + Area B= 3+6

= 9m

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A car has a mass of 1,000 kilograms. The weight of the car is blank newtons. Use g = 9.8 N/kg for gravity.

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The weight of an object is mass*acceleration. In this case mass*g.
1000*9.8=9800
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Consider a grain of table salt which is made of positive

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Answer:

Force, $F=8.23\times 10^{-8}\ N$

Explanation:

It is given that,

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4 years ago

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A football player running at a velocity of 9.0m/s hits the goal post and come to a stop in 0.0sec . calculate his acceleration.

myrzilka [38]

The acceleration during uniform motion in ft/sec is -98.42.

We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule

vt = vo + a . t

vt² = vo² + 2a . s

s = vo . t + 1/2 . a . t²

where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.

From the question above, we know that

vo = 9 m/s

t = 0.3 s

vt = 0 m/s

Calculate the acceleration in m/s

vt = vo + at

0 = 9 + a.0.3

a = -9/0.3

a = -30 m/s²

Convert to feet/s

a = -30 m/s

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Find more on uniform motion at: brainly.com/question/28040370

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4 0

1 year ago

A cart on a horizontal, linear track has a fan attached to it. The cart is positioned at one end of the track, and the fan is tu

kompoz [17]

Answer:

$F = 0.0566 \ N$

$t = 6.147 \ s$

Explanation:

From the question we are told that

The distance travel in 4.22 s is $s = 1.44 \ m$

The mass of the cart plus the fan is $m = 350 \ g = 0.35 \ kg$

Generally from kinematic equation we have that

$s = ut + \frac{1}{2} * a * t^2$

Here u is the initial velocity with value $u = 0 \ m/s$

$1.44= 0 * t + \frac{1}{2} * a * 4.22^2$

=> $a = 0.1617 \ m/s^2$

Generally the net force is

$F = m * a$

=> $F = 0.35 * 0.1617$

=> $F = 0.0566 \ N$

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The distance considered is $s_1 = 1.63 \ m$

Generally the new acceleration of the cart is mathematically represented as

$F = M * a_1$

=> $a_1 = \frac{F}{M}$

=> $a_1 = \frac{0.0566}{0.656}$

=> $a_1 = 0.08628 \ m/s^2$

Gnerally from kinematic equation we have

$s = ut + \frac{1}{2} * a_1 * t ^2$

Here u is the initial velocity and the value is zero because it started from rest

=> $1.63 = 0 * t + \frac{1}{2} * 0.08628* t ^2$

=> $t = 6.147 \ s$

6 0

3 years ago