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3 years ago

Please help me I really need it

Physics

1 answer:

tensa zangetsu [6.8K]3 years ago

4 0

Answer:

A 1.5 metres per second squared B 0 C 6 0.5

b) 9m

Explanation:

a= v-a/t

a= acceleration measured in metres per second squared

v= final speed measured in metres per second

u= initial speed measured in metres per second

t= time measured in second

a=v-a/t

a= 3-0/2

a= 1.5 metres per second squared

Distance in a velocity time graph = area under

To calculate the distance in the first 4 seconds

You divide the graph into triangles and rectangles

Area A (triangle )= 1/2 × base × height

=1÷2 ×2×3

= 3m

Area B (rectangle)= L×B

=2×3

=6m

Area A + Area B= 3+6

= 9m

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Option C is correct. It has a high frequency. Wavelength is inversly proportional to the frequency. For short-wavelength, the frequency will be high.

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3 years ago

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1) -7.14 N

2) +2.70 N

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In order to find the x-component of the resultant force, we have to resolve each force along the x-axis.

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$180^{\circ}-61^{\circ}$

so its x-component is

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Therefore its x-component is

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So, the x-component of the resultant force is

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In order to find the y-component of the resultant force, we have to resolve each force along the y-axis.

The first force is 8.00 N and is directed at an angle of 61.0° above the negative x axis in the second quadrant: as we said previously, the angle with respect to the positive x axis is

$180^{\circ}-61^{\circ}$

so its y-component is

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F₂ has a magnitude of 5.40 N and is directed at an angle of 52.8° below the negative x axis in the third quadrant: as we said previously, its angle with respect to the positive x-axis is

$180^{\circ}+52.8^{\circ}$

Therefore its y-component is

$F_{2y}=(5.40)(sin (180^{\circ}+52.8^{\circ}))=-4.30 N$

So, the y-component of the resultant force is

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$F_y=2.70 N$ is the y-component

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