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Delicious77 [7]
3 years ago
6

A car with a mass of 600 kg is traveling at a velocity of 10 m/s. How much kinetic energy does it have? The car has J of kinetic

energy.
Physics
1 answer:
konstantin123 [22]3 years ago
5 0
The kinetic energy of an object is given by:
K= \frac{1}{2}mv^2
where m is the mass of the object and v its velocity. 

The car in this problem has a mass of m=600 kg and a velocity of v=10 m/s, therefore if we put these numbers into the equation, we find the kinetic energy of the car:
K= \frac{1}{2}mv^2= \frac{1}{2}(600 kg)(10 m/s)^2=30000 J
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solmaris [256]

Answer: Hello! Apparently, your question is incomplete. Those were sentences in which you had to complete with missing information, so here we go:

1- Our entire solar system orbits around the center of the MILKY WAY GALAXY about once every 230 million years.

2- The Milky Way and Andromeda galaxies are among a few dozen galaxies that make up our LOCAL GROUP.

3 - The Sun appears to rise and set in our sky because Earth ROTATES once each day.

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3 0
3 years ago
A thin oil slick (no=1.50) floats on water (nw=1.33). When a beam of white light strikes this film at normal incidence from air,
Sedbober [7]

Answer:

The (minimum) thickness of the oil slick is 325 nm.

Explanation:

Let the (minimum) thickness of the oil slick = t_{o}

Therefore:

2t_{o} = (m_{red}+\frac{1}{2})*λ_{red}/n_{o}       (1)

similarly,

2t_{o}=(m_{violet}+\frac{1}{2})*λ_{violet}/n_{o}                                (2)

Thus, equation 1 = equation 2

(m_{red}+\frac{1}{2})*λ_{red} /n_{o} = (m_{violet}+\frac{1}{2})*λ_{violet}/n_{o}

Where:

λ_{red} = 650 nm

λ_{violet} = 390 nm

n_{o} = 1.5

Therefore:

\frac{2m_{violet}+1 }{2n_{red}+1 }=650/390=5/3

This shows that,

m_{violet}=2

m_{red}=1

Thus, using equation 2

t_{o}=\frac{5*390}{2*2*1.5} =325 nm

6 0
3 years ago
A graduated cylinder contains 62 ml of water. When a small metal block is added to the water, the volume of the water increases
lawyer [7]

Answer:

The density of the block is 7.4g/ml.

Explanation:

We can determine the volume of the metal block by taking the difference between the volumes measured in the graduated cylinder:

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Now, as we know that the average density of an object is calculated dividing its mass by its volume, we can calculate the density ρ of the metal block using the expression:

\rho_{block}=\frac{m_{block}}{V_{block}}\\\\\rho_{block}=\frac{26g}{3.5ml}\\\\\rho_{block}=7.4\frac{g}{ml}

Finally, it means that the density of the metal block is 7.4g/ml.

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