Answer:

Explanation:
Given:
height above which the rock is thrown up, 
initial velocity of projection, 
let the gravity on the other planet be g'
The time taken by the rock to reach the top height on the exoplanet:
where:
final velocity at the top height = 0 
(-ve sign to indicate that acceleration acts opposite to the velocity)

The time taken by the rock to reach the top height on the earth:



Height reached by the rock above the point of throwing on the exoplanet:

where:
final velocity at the top height = 0 


Height reached by the rock above the point of throwing on the earth:



The time taken by the rock to fall from the highest point to the ground on the exoplanet:
(during falling it falls below the cliff)
here:
initial velocity= 0 



Similarly on earth:

Now the required time difference:


Answer: The time of contact will be 0.006 seconds.
Explanation:
An impulse of a force is the product of average force and the time interval when the force acts.
Mathematically,

Where,
J = impulse = 3.6 Ns
F = Force = 600N
= Time = ?s
Putting the values in above equation, we get:

t = 0.006 seconds
Hence, the time of contact will be 0.006 seconds.
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7.11x 10⁶J
Explanation:
Given parameters:
Speed of light = 3 x 10⁸m/s
Mass of object = 23.7g = 0.0237kg
Unknown:
Energy = ?
Solution:
From Einstein's equation, we see that mass and energy are equivalent using the expression below:
E = mc²
Substituting the parameters:
E = 3 x 10⁸ x 0.0237 = 7.11x 10⁶J
Learn more:
Energy brainly.com/question/5381158
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