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Talja [164]
3 years ago
5

Name two other elements that have properties that are similar to those of the element rubidium and why would they.

Chemistry
1 answer:
Andrei [34K]3 years ago
4 0
Answer is potassium and sodium. They are in the same group and that means they have the same properties. They are all alkali metals
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Which chemical out of the following 4 is the most dangerous? Glucose, benzene,acetone, ether
Lelechka [254]

Answer:

B.

Explanation: hope this helps

Benzene

5 0
1 year ago
What kind of change occurs when I’ve becomes liquid water
gregori [183]

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Its a physical

theres no chemical properties involved.

Explanation:

Brainliest please

6 0
3 years ago
Jamie rolls a 6-sided die 30 times and determines that the experimental probability of rolling a 2 is Start Fraction 1 over 15 E
anyanavicka [17]

Answer:

Conduct more trials

Explanation:

Theoretical Probability can be defined as what someone is expecting to happen

Experimental Probability on the other hand, is defined as what actually happens.

Probability is usually calculated in the same way for experimental probability and that of theoretical probability. You divide the total number of possible ways in which a particular outcome can happen, by the total number of outcomes itself.

In Experimental probability, the more times a probability is tried, it gets closer and even more closer to theoretical probability.

So, for the question, Jamie should improve the number of tries more, so as to get his experimental probability results to be closer to the theoretical probability result.

8 0
3 years ago
Hich of the following is an oxidation-reduction reaction?
KiRa [710]

The oxidation-reduction reaction from the reactions above is

ZnS(s) + 2O2(g) ------ ZnSO4(s)

<h3>What is redox reactions?</h3>

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So therefore, the oxidation-reduction reaction from the reactions above is

ZnS(s) + 2O2(g) ------ ZnSO4(s)

Learn more about oxidation-reduction reactions:

brainly.com/question/10668495

#SPJ1

6 0
2 years ago
i have an unknown volume of gas at a pressure of 0.50 atm a temperature of 325 k. If i raise the pressure to 1.2 atm, decrease t
Ronch [10]
Assuming that the number of mols are constant for both conditions:
\frac{P_1V_1}{T_1} =  \frac{P_2V_2}{T_2}
Now you plug in the given values. V_1 is the unknown. 
\frac{0.50 atm*V_1}{325K} = \frac{1.2 atm* 48 L}{230K}&#10;
Separate V_1
V_1= \frac{1.2 atm* 48 L * 325K }{230K*0.50 atm }
V= 162.782608696 L 

There are 2 sig figs

V= 160 L
3 0
3 years ago
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