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AnnZ [28]
4 years ago
8

What type of figure is this

Engineering
1 answer:
Vlad1618 [11]4 years ago
8 0
The answer is Ur moms figure
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The yield strength of mild steel is 150 MPa for an average grain diameter of 0.038 mm ; yield strength is 250 MPa for average gr
djyliett [7]

Answer:

Explanation:

Hall-Petch equation provides direct relations between the strength of the material and the grain size:

σ=σ0+k/√d , where d- grain size, σ- strength for the given gran size, σ0 and k are the equation constants.

As in this problem, we don't know the constants of the equation, but we know two properties of the material, we are able to find them from the system of equations:

σ1=σ0+k/√d1

σ2=σ0+k/√d2 , where 1 and 2 represent 150MPa and 250MPa strength of the steel.

Note, that for the given problem, there is no need to convert units to SI, as constants can have any units, which are convenient for us.

From the system of equations calculations, we can find constant: σ0=55.196 MPa, k=18.48 MPa*mm^(0.5)

Now we are able to calculate strength for the grain diameter of 0.004 mm:

σ=55.196+18.48/(√0.004)=347.39 MPa

The strength of the steel with the grais size of 0.004 mm is 347.39 MPa.

6 0
4 years ago
Hey, Whos sooo bored right now? Also who is going to get a pet soon? I find the perfect pet for you for free!
AleksAgata [21]

Answer:

I love animals, but I dont need anymore. I have 7 cats

3 0
3 years ago
3.8. Describe the two alternatives for specifying structural constraints on relationship types. What are the advantages and disa
forsale [732]

Answer: CARDINALITY RATIO AND PARTICIPATION

ADVANTAGE

CARDINALITY RATIO

(THEY ARE USED TO SIMPLIFY DESIGNS)

DISADVANTAGE OF CARDINALITY RATIO IS THAT

(YOU CAN NOT SPECIFY A GIVEN NUMBER TO BE MAXIMUM)

ADVANTAGE OF PARTICIPATION CONSTRAINT IS THAT

(IT SHOWS WETHER THE EXISTENCE OF AN ENTITY IS DEPENDENT ON ITS RELATIONSHIPS WITH ANOTHER ENTITY)

DISADVANTAGE OF PARTICIPATION CONSTRAINT

(IT IS A COSTLY AFFAIR USING BOTH MODELS TO EXPRESEE RELATIONSHIPS).

Explanation:CARDINALITY RATIO specifies that maximum number of relationships an entity can engage itself in.

Participation constraint is a constraint that

Specifies whether the existence of an entity depends on its Relationships to another entity, it specifies the the minimum number of relationship instances that an entity can participate in

It is also minimum cardinality constraint,it has two types named as Total participation and partial participation.

7 0
4 years ago
A closed, rigid tank is filled with a gas modeled as an ideal gas, initially at 27°C and a gage pressure of 300 kPa. If the gas
ch4aika [34]

Answer:

gauge pressure is 133 kPa

Explanation:

given data

initial temperature T1 = 27°C = 300 K

gauge pressure = 300 kPa = 300 × 10³ Pa

atmospheric pressure = 1 atm

final temperature T2 = 77°C = 350 K

to find out

final pressure

solution

we know that gauge pressure is = absolute pressure - atmospheric pressure so

P (gauge ) = 300 × 10³ Pa - 1 × 10^{5} Pa

P (gauge ) = 2 × 10^{5} Pa

so from idea gas equation

\frac{P1*V1}{T1} = \frac{P2*V2}{T2}   ................1

so {P2} = \frac{P1*T2}{T1}

{P2} = \frac{2*10^5*350}{300}

P2 = 2.33 × 10^{5} Pa

so gauge pressure = absolute pressure - atmospheric pressure

gauge pressure = 2.33 × 10^{5}  - 1.0 × 10^{5}

gauge pressure = 1.33 × 10^{5} Pa

so gauge pressure is 133 kPa

4 0
3 years ago
Determine the COP of a refrigerator that removes heat from the food compartment at a rate of 5160 kJ/h for each kW of power it c
Mars2501 [29]

Answer:

COP_R=1.433\\Q_H=2.433kW

Explanation:

Hello,

In this case, the coefficient of performance of this refrigerator is defined in terms of the removed heat and the work input as:

COP_R=\frac{Q_{L}}{W_{in}} =\frac{5160\frac{kJ}{h}*\frac{1h}{3600s} }{1kJ/s} =1.433

Moreover, the rate of heat rejection to the outside air tuns out:

W_{in}=Q_H-Q_L\\Q_H=W_{in}+Q_L=1kW+5160\frac{kJ}{h}*\frac{1h}{3600s} =2.433kW

Best regards.

3 0
3 years ago
Read 2 more answers
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