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3 years ago

What do you think is the difference between being imaginative in doing science and Doing pseudoscience?

1 answer:

7 0

I would say that being imaginative in science means finding new ways to find or analyse the data, but which do not make the data false or which do not manipulate the data. Being imaginative in science should not cross the boundary of making the science not reliable

Being imaginative in pseudoscience could mean manipulating the data or even making experiments in such a way as to only obtaining specific data or throwing away certain data.

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A hydraulic cylinder causes the distance between points A and O to decrease at a constant rate of 3 inches per second. a) Determ

Ierofanga [76]

Answer:

a) The speed of the slider is 4.28 in/s

b) The velocity vector is 2.33 in/s

Explanation:

a) According to the diagram 1 in the attached image:

$r_{C/A} =12*cos55i-12*sin55j\\r_{C/A}=6.883i-9.829j$

Also:

$v_{C} =v_{A}+w_{AC}*r_{C/A}\\v_{Ci}=-3j+\left[\begin{array}{ccc}i&j&k\\0&0&w_{AC} \\6.883&-9.829&0\end{array}\right]\\v_{Ci}=-3j+(0+9.829w_{AC} i-(0-6.883w_{AC})j\\v_{Ci}=9.829w_{AC}i+(-3+6.883w_{AC})j$

If we comparing both sides of the expression:

$-3+6.883w_{AC}=0\\w_{AC}=0.435rad/s$

$v_{C}=9.829*0.435=4.28in/s$

b) According to the diagram 2 in the attached image:

$r_{C/A}=12cos50i-12sin50j=7.713i-9.192j\\r_{B/C}=-3.856i+4.596j$

$v_{C}=v_{A}+w_{AC}r_{C/A}\\v_{C}=-3j+\left[\begin{array}{ccc}i&j&k\\0&0&w_{AC}\\7.713&-9.192&0\end{array}\right] \\v_{Ci}=-3j+(9.192w_{AC})i+7.713w_{AC}j\\v_{Ci}=9.192w_{AC}i+(7.713w_{AC}-3)j$

Comparing both sides of the expression:

$7.713w_{AC}-3=0\\w_{AC}=0.388rad/s\\v_{C}=3.575i$

$v_{B}=v_{C}+w_{AC}r_{B/C}\\v_{B}=3.57i+\left[\begin{array}{ccc}i&j&k\\0&0&0.388\\-3.856&4.59&0\end{array}\right] \\v_{B}=3.57i+(0-1.78)i-(0+1.499)j\\v_{B}=1.787i-1.499j\\|v_{B}|=\sqrt{1.787^{2}+1.499^{2} } =2.33in/s$

6 0

3 years ago

A 23.3 kg crate is pushed with a force of 944 N for 36.0 seconds, moving the crate a distance of 12.4 m. How much power was used

tigry1 [53]

Explanation:

$p = \frac{f \times s}{t}$

power = Force × distance /time

power = 944N × 12.4m/36secs

power = (944×12.4/36)Nms—¹

power = 390.2Nms—¹ or 390.2Watts or 390.2Js—¹

8 0

3 years ago

Calculate the magnitude of the normal force on a 25.2 kg block in the following circumstances. (Enter your answers in N.) HINT (

irga5000 [103]

Answer:

when the body is resting N = 246.96 N

when the body is resting on a tilted surface N = 212.12 N.

when the body is in a elevator N = 317.036 N

Explanation:

when the block is resting on a stationary surface the normal force is balanced by the weight of the body.

weight of the body = mg = 25.2×9.8 = 246.96 N

therefore normal force = 246.98 N.

when the block is resting on a tilted surface the normal force will be balanced by the $\cos \theta$ component of the weight where Ф is the angle of inclination.

therefore N = mg $\cos \Phi$

N= 212.12 N.

when the block is resting on a elevator that is accelerated upward the normal force will be the sum of weight and force due to acceleration ma

therefore N = 246.98 + 25.2×2.78

N = 317.036 N

5 0

4 years ago

A bar B made of some material is attracted by a magnet. Is the bar B magnetised ?

Dvinal [7]

Answer:

No, it is not magnetized.

Explanation:

Bar B does not necessarily have to be magnetized before it can be attracted to a magnet. It just has to be a magnetic material such as Iron.

If bar B were magnetized, it could either be attracted or repelled by the magnet since this would depend on the side of the pole of bar B facing it.

Since we are not given any information about bar B other than it is attracted to the magnet, it is thus not magnetized.

7 0

3 years ago

Lithium

tigry1 [53]

Answer:d

Explanation:

6 0

3 years ago