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ikadub [295]
3 years ago
13

Can you answer my questions. Please help me ​

Physics
1 answer:
earnstyle [38]3 years ago
8 0

Answer:

answered it.................

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Which most accurately describes the path that sound​ travels??
emmainna [20.7K]
What are the options ?
6 0
2 years ago
What best describes a sound wave? transverse and electromagnetic longitudinal and mechanical longitudinal and electromagnetic tr
GalinKa [24]

Sound needs medium to travel and it can not travel without medium

so sound wave is a travelling wave

now we also know that sound wave propagate in form of rarefaction and compression.

So all medium particles travel in the direction of wave only

so it is a longitudinal wave also

so correct answer will be

<em>mechanical longitudinal </em>

7 0
3 years ago
Read 2 more answers
Calculate the number of free electrons and holes (in m-3) in an intrinsic semiconductor that has electron and hole mobilities of
allochka39001 [22]

Answer:

ni = 2.04e19

Explanation:

we know that in semiconductor like intrinsic, when electron leave the band, it leave a hole in valence band so we have

n = p = ni

from intrinsic carrier concentration

\sigma = n\left | e \right | \mu_e + n\left | e \right | \mu_h

\sigma = ni\left | e \right | \mu_e  + ni\left | e \right | \mu_h

\sigma = ni \left | e \right | ( \mu_e + \mu_h)

1.7 = ni * 1.6*10^{-19} * (.35 + .17)

ni = 2.014 *10^{19} m^{-3}

ni = 2.04e19

5 0
2 years ago
Why can you see your own reflected image in a mirror but not on a dry, painted wall?
kaheart [24]
A wall uses diffuse reflection while a mirror uses specular reflection. For example, when parallel light rays enter a mirror, they remain parallel when exiting the mirror, allowing you to see a reflection of the light rays. On the contrary, when incident light rays enter a wall which is painted, the rays scatter, not allowing you to see anything but a painted wall. 
7 0
3 years ago
n electromagnetic wave in vacuum has an electric field amplitude of 611 V/m. Calculate the amplitude of the corresponding magnet
enot [183]

Answer:

The  corresponding  magnetic field is  

Explanation:

From the question we are told that

    The electric field amplitude is  E_o   =  611\  V/m

   

Generally the  magnetic  field amplitude is  mathematically represented as

              B_o  =  \frac{E_o }{c }

Where c is the speed of light with a constant value

         c = 3.0 *0^{8} \ m/s

So  

        B_o   =  \frac{611 }{3.0*10^{8}}

         B_o   =  2.0 4 *10^{-6} \  Vm^{-2} s

Since 1  T  is  equivalent to  V  m^{-2} \cdot  s

         B_o  =  2.0 4 *10^{-6} \ T

6 0
3 years ago
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