<u>Answer:</u> The temperature of the system will be 1622 K
<u>Explanation:</u>
The equation relating the pre-exponential factor and activation energy follows:

where,
D = diffusion coefficient = 
= pre-exponential constant = 
= activation energy of iron in cobalt = 273,300 J/mol
R = Gas constant = 8.314 J/mol.K
T = temperature = ?
Putting values in above equation, we get:

Hence, the temperature of the system will be 1622 K
For a reaction rate that increases by a factor of 655 in the presence of a catalyst at 37°C, the activation energy of the new pathway is mathematically given as
Ea2=89.28JKoule/mol
<h3>What is the activation energy of the new pathway, all other factors being equal?</h3>
Generally, the equation for the rate constant is mathematically given as
K=Ae^{Ea1/Rt}
Therefore

Ea2=89286.083Joule/mol
In conclusion, the activation energy
Ea2=89.28JKoule/mol
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brainly.com/question/13439286
Answer:
B
Explanation:
If someone was to call your picture calligraphy it mean beautiful graphics so theres your answer
this shows that magnesium is higher in the reactivity series than lead.
I don't think there can be an ionic equation written because both components are in solid form and neither is in an aqeuos state.
Answer:

Explanation:
The temperature and amount of gas are constant, so we can use Boyle’s Law.

Data:

Calculations:
