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LekaFEV [45]
3 years ago
12

The missing components in the table to the right are indicated with orange letters. Complete table by filling in the correspondi

ng numbers or symbols below

Chemistry
1 answer:
V125BC [204]3 years ago
4 0

Answer :

A = In

B = 27

C = 73

D = 49

E = 56

F = 54

G = 66

H = 108

I = 32

Explanation :

Atomic number is defined as the number of protons or number of electrons.

Atomic number = number of protons = number of electrons

Mass number is defined as the sum of number of protons and number of neutrons.

Number of neutrons = Mass number - Number of protons

Number of electrons = Number of protons - charge

Element        Number of       Number of        Number of        Atomic

symbol          protons            electrons          neutrons           mass

  Co                  27                     27                      31                    58

  In                    49                     49                     66                   115

  Ta                   73                     73                     108                  181

  Ba²⁺                56                    54                      81                   137

  S²⁻                  16                      18                      16                    32

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Find the percent composition of OXYGEN in Manganese (III) nitrate, Mn(NO3)3.
BaLLatris [955]

Answer:

59.8%

Explanation:

First find the Mr of manganese (III) nitrate.

Mr of Mn(NO₃)₃ = 54.9 + (14 × 3) + (16 × 3 × 3) = <u>240.9</u>

Since we have to find the percentage composition of oxygen, we need to find the Mr of oxygen in the compound, which is:

Mr of (O₃)₃ = (16 × 3) × 3 = <u>144</u>

Now we can find percentage composition / percentage by mass of oxygen.

% composition = \frac{Mr\ of\ oxygen\ in\ compound}{Mr\ of\ compound} × 100

% composition = \frac{144}{240.9} × 100 = <u>59.776%</u>

∴ % compostion of oxygen in maganese(III)nitrate is 59.8% (to 3 significant figures).

8 0
2 years ago
What is Keq for the reaction N₂ + 3H2 = 2NH3 if the equilibrium
hram777 [196]

The Keq for the reaction N₂ + 3H2 = 2NH3 if the equilibrium concentrations are Keq = 1.5. The correct option is D.

<h3>What is Keq?</h3>

Keq is the ratio of the concentration of reactant to the concentration of the product.

The balanced equation is

N₂ + 3H₂  = 2NH₃

The equilibrium constant is \rm \dfrac{[NH_3]^2}{[N_2]\; [H_2]^3}

The given concentrations of the compounds have been:

Ammonia = 3 M

Nitrogen = 1 M

Hydrogen = 2 M

\rm \dfrac{9}{1\times 8} = 1.5

Thus, the correct option is D. Keq = 1.5.

Learn more about Keq

brainly.com/question/24059926

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3 0
2 years ago
A jet airplane reaches 750 km/h on a certain flight. What distance does it cover in <br> 10 min?
malfutka [58]

The distance that jet covered in 10 min is 125 Km

calculation

distance = speed  x time

speed=750 km/h

time= 10/60hrs

=750 x10/60=125 Km

3 0
3 years ago
Read 2 more answers
. If this same atom with 22 protons and 19 electrons were to gain 3 electrons, the net charge on the atom would be
mina [271]

Answer:

neutral

Explanation:

19+3=22

22 protons & 22 neutrons --> neutral net charge

3 0
3 years ago
23.5 L of h2 is stored at a pressure of 58.7 Kpa what volume would the gas take up at stp
stepan [7]

Answer:-  13.6 L

Solution:- Volume of hydrogen gas at 58.7 Kpa is given as 23.5 L. It asks to calculate the volume of hydrogen gas at STP that is standard temperature and pressure. Since the problem does not talk about the original temperature so we would assume the constant temperature. So, it is Boyle's law.

Standard pressure is 1 atm that is 101.325 Kpa.

Boyle's law equation is:

P_1V_1=P_2V_2

From given information:-

P_1 = 58.7 Kpa

V_1 = 23.5 L

P_2 = 101.325 Kpa

V_2 = ?

Let's plug in the values and solve it for final volume.

58.7Kpa*23.5L=101.325Kpa*V_2

On rearranging the equation for V_2

V_2=\frac{58.7Kpa*23.5L}{101.325Kpa}

V_2 = 13.6 L

So, the volume of hydrogen gas at STP for the given information is 13.6 L.

3 0
3 years ago
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