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makkiz [27]
3 years ago
7

Which is a conjugate pair in the following equilibrium? H2C2O4(aq) + HPO4(aq) 2- HC2O4(aq)- + H2PO4(aq)-

Chemistry
2 answers:
blagie [28]3 years ago
8 0

Explanation

According to Bronsted Lowry acid-base theory:

  • Conjugate acid is a species formed by the addition of proton to the base. or species . Or those chemical species which accepts protons.
  • Conjugate base is a species formed by the removal one proton from the acid. Or those chemical species which donates the proton.
  • Here proton is H^+

H_2C_2O_4(aq)+HPO_{4}^{2-}(aq)\rightarrow HC_2O_{4}^-(aq) + H_2PO_{4}^-(aq)

1) Acid will form conjugate base: H_2C_2O_4(aq)   forming conjugate base H_1C_2O_{4}^-(aq)

2) Base will form conjugate acid :HPO_{4}^{2-} forming conjugate acid H_2PO_{4}^{-}(aq)

sweet [91]3 years ago
3 0
 its B on plato .. ... . .. . . . . . . .. 
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How many grams of hydrogen chloride can be produced from 1g of hydrogen and 55g of chlorine? What is the limiting reactant?
vova2212 [387]

Answer:

The limiting reactant is hydrogen, and the grams HCl produced is 36.175 g.

Explanation:

Balanced equation is 2 H + Cl2 = 2 HCl.

First thing, convert grams to moles via using molar mass.

Molar mass for hydrogen is 1.0079 g/mol. 1g x 1 mol / 1.0079 g = 0.99216 mol.

Molar mass for chlorine is 70.906 g/mol. 55g x 1 mol / 70.906 g = 0.7756748 mol.

Next, determine which is the limiting reactant - probably the fastest way to do it is just to take one of the reactants, say it's the limiting one, and calculate how much of the other reactant would be needed if that really was the limiting reactant, and then compare it to the actual moles of reactant available.

If hydrogen was the limiting reactant at 0.992 mol, you'd need .496 mol of Cl2 to complete the reaction.

If chloride was the limiting reactant at 0.776 mol, you'd need 1.55 mol of H to complete the reaction.

Comparing these numbers to the amounts we actually have available, the limiting reactant is hydrogen.

Once you've determined that, just plug in the amounts to the balanced equation to get the number of moles of HCL produced, which in this case, is just 0.992 mol.

Now, reverse the process that you took to get the moles of reactant, and you have the grams of product produced.

0.992 mol x 36.4609 g / 1 mol = 36.175 g.

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