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makkiz [27]
3 years ago
7

Which is a conjugate pair in the following equilibrium? H2C2O4(aq) + HPO4(aq) 2- HC2O4(aq)- + H2PO4(aq)-

Chemistry
2 answers:
blagie [28]3 years ago
8 0

Explanation

According to Bronsted Lowry acid-base theory:

  • Conjugate acid is a species formed by the addition of proton to the base. or species . Or those chemical species which accepts protons.
  • Conjugate base is a species formed by the removal one proton from the acid. Or those chemical species which donates the proton.
  • Here proton is H^+

H_2C_2O_4(aq)+HPO_{4}^{2-}(aq)\rightarrow HC_2O_{4}^-(aq) + H_2PO_{4}^-(aq)

1) Acid will form conjugate base: H_2C_2O_4(aq)   forming conjugate base H_1C_2O_{4}^-(aq)

2) Base will form conjugate acid :HPO_{4}^{2-} forming conjugate acid H_2PO_{4}^{-}(aq)

sweet [91]3 years ago
3 0
 its B on plato .. ... . .. . . . . . . .. 
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if you mixed 72.9g hydrochloric acid(aq) with 150g silver acetate(aq), what would be the limiting reagent?​
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Answer:

                      Silver Acetate would be the Limiting Reagent.

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                    The balance chemical equation for the given double displacement reaction is as;

                            HCl + AgC₂H₃O₂ → AgCl + HC₂H₃O₂

Step 1: <u>Calculate Moles of Starting Materials:</u>

Moles of HCl:

                      Moles  =  Mass / M.Mass

                      Moles  =  72.9 g / 36.46

                      Moles =  1.99 moles

Moles of AgC₂H₃O₂:

                      Moles  =  150 g / 166.91 g/mol

                      Moles  =  0.898 moles

Step 2: <u>Find out Limiting reagent as:</u>

According to balance chemical equation.

              1 mole of HCl reacts with  =  1 mole of AgC₂H₃O₂

So,

         1.99 moles of HCl will react with  =  X moles of AgC₂H₃O₂

Solving for X,

                     X =  1.99 mol × 1 mol / 1 mol

                     X =  1.99 mol of AgC₂H₃O₂

Hence, to completely consume 1.99 moles of Hydrochloric acid we will require 1.99 moles of Silver Acetate, But, we are provided with only 0.898 moles of Silver Acetate. This means Silver Acetate will consume first in the reaction therefore, it is the LIMITING REAGENT.

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