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3 years ago

As the magnetic field increases, which of the following also increases

Physics

1 answer:

Leokris [45]3 years ago

8 0

The answer is AREA .............

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Match: The graph below shows the potential and kinetic energy curves for a pendulum. Label each pendulum image with the correspo

Mariana [72]

Top right = B
bottom left = A
bottom right = C

4 0

3 years ago

Consider an acrylic sheet of thickness L = 5 mm that is used to coat a hot, isothermal metal substrate at Th = 300°C. The proper

Ad libitum [116K]

Answer:

74.52s

Explanation:

The solution is shown in the picture below

7 0

3 years ago

Which of these is a possible disadvantage of using wind as a source of

gizmo_the_mogwai [7]

Answer:

D. Wind turbines take up a lot of space.

Explanation:

In wind turbines the kinetic energy received by the air molecules is converted into electrical energy by the use of turbines

So here in order to get more kinetic energy from air we need more crossectional area of the wind mill to interact with the air

So here we need the large size of turbines

so this is the main disadvantage of the wind turbines because it needs large area to install the whole setup also the efficiency of this turbine is small so it needs large number of wind mills to setup good output power

so correct answer will be

D. Wind turbines take up a lot of space.

3 0

3 years ago

Read 2 more answers

Un tren va a una velocidad de 18m/s frena y se detiene en 15s calcula su aceleracion y la distancia recorrida al frenar

Rudiy27

Answer:

Acceleration is -1.2 m/s² and distance covered is 135 m.

Explanation:

A train going at a speed of 18m / s brakes and stops in 15s calculates its acceleration and the distance traveled when braking

Given that,

The initial speed of the train, u = 18 m/s

Final speed, v = 0

Time, t = 15 s

We need to find acceleration and distance traveled when braking. Let a is acceleration and distance traveled.

Acceleration,

$a=\dfrac{v-u}{t}\\\\a=\dfrac{0-18}{15}\\\\a=-1.2\ m/s^2$

Using third equation of motion,

$v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{0^2-18^2}{2\times (-1.2)}\\\\d=135\ m$

Hence, acceleration is -1.2 m/s² and distance covered is 135 m.

3 0

3 years ago

Average formula is...?

Kruka [31]

Answer:

total sum of all numbers/ number of items in the set

Explanation:

3 0

3 years ago