3 years ago

If you weigh 637 N on Earth's surface, how much would you weigh on the planet Mars?

Physics

1 answer:

vivado [14]3 years ago

4 0

Answer:

To get your answer multiply 637N by 10N/kg to get 6370kg

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Speed versus Time

sukhopar [10]

The answer would be c

7 0

3 years ago

một động cơ nhiệt khi hoạt động nhiệt lượng mà nó nhận vào gấp bốn lần công mà nó thực hiện. Hiệu suất của động cơ là?

OlgaM077 [116]

$\frac{1}{4} = 0.25 = 25\%$

6 0

3 years ago

You are walking around your neighborhood and you see a child on top of a roof of a building kick a soccer ball. The soccer ball

const2013 [10]

Answer:

The building is 61.19 m tall, approximately.

Explanation:

From the parabollic movement trayectory equation,

$y=H+\frac{v_{0y}}{v_x}x-\frac{1}{2v_x^2}gx^2,$

where H is the initial height of the ball and $v_{oy}$ and $v_x$ the inital velocities in the vertical and horizontal direction, respectively; we have

$H=y-\frac{v_{0y}}{v_x}x+\frac{1}{2v_x^2}gx^2$ .

In this case, the ball landed at the coordinates $\left(x,y\right)=\left(61,0\right)$ , so

$H=0-\frac{17\sin\left(43\deg\right)}{17\cos\left(43\deg\right)}\times 61+\frac{1}{2\left(17\cos\left(43\deg\right)\right)^2}\times 9.81\times 61^2 \approx 61.19$ .