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stepladder [879]
3 years ago
10

If you weigh 637 N on Earth's surface, how much would you weigh on the planet Mars?

Physics
1 answer:
vivado [14]3 years ago
4 0

Answer:

To get your answer multiply 637N by 10N/kg to get 6370kg

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A 500 μF capacitor is wired in series with a 5 V battery and a 20 kΩ resistor. What is the voltage across the capacitor after 20
liq [111]

Answer:

Explanation:

It is a question relating to charging of capacitor . For charging of capacitor , the formula is as follows.

Q = CV ( 1 - e^{-\lambda\times t} )

λ = 1/CR , C is capacitance and R is resistance.

= 1/(500 x 10⁻⁶ x 20 x 10³ )

= .1

λ t = .1 x 20

λ t = 2

CV = 500 X 10⁻⁶ X 5

= 2500 X 10⁻⁶ C

Q = 2500 x 10⁻⁶ ( 1 - e^{-2} )

= 2500 x 10⁻⁶ x .86566

= 2161.66 μ C .

voltage = Charge / capacitor

2161.66 μ C  / 500μ F

= 4.32 V

3 0
4 years ago
Read 2 more answers
A machine produces 4,000 J of work in 5 seconds. how much power does the machine produce.
ad-work [718]

Explanation:

Power is defined as the work done per unit time or

P = \dfrac{\Delta W}{\Delta t}

\;\;\;\;= \dfrac{4000\:\text{J}}{5\:\text{s}} = 800\:\text{Watts}

5 0
3 years ago
What part of the water is affected by a wave in deep water
krok68 [10]
Wave base is the most affected by a wave in deep water. :]
5 0
4 years ago
View this and help out??
Zina [86]
I would say b as well. I’m sorry if it’s wrong
5 0
3 years ago
A 1502.7 kg car is traveling at 33.1 m/s when
Bond [772]

By definition of average acceleration,

<em>a</em> = (20 m/s - 33.1 m/s) / (4.7 s) ≈ -2.78 m/s²

Vertically, the car is in equilibrium, so the net force is equal to the friction force in the direction opposite the car's motion:

∑ <em>F</em> = (1502.7 kg) (-2.78 m/s²) ≈ -4188.38 N ≈ -4200 N

If you just want the magnitude, drop the negative sign.

5 0
3 years ago
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