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2 years ago

If you weigh 637 N on Earth's surface, how much would you weigh on the planet Mars?

Physics

1 answer:

vivado [14]2 years ago

4 0

Answer:

To get your answer multiply 637N by 10N/kg to get 6370kg

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In which situation is the object experiencing unbalanced forces? A) A box resting on a horizontal floor. B) A car slowing as it

evablogger [386]

"Unbalanced forces" show themselves as a change in the speed
or direction of an object's motion.

The only choice where the speed or direction of motion is changing
is the car that's slowing down for the light.

3 0

2 years ago

Read 2 more answers

What is meant by action and reaction

ElenaW [278]

Answer: action and reaction forces and are the subject of Newton's third law of motion. Formally stated, Newton's third law is: For every action, there is an equal and opposite reaction

Explanation:

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2 years ago

If the atoms of one object (initially neutral) have electrons rubbed off through friction with a second object, the first object

snow_lady [41]

Positive. The 1st object loses electrons and will thus have an imbalance of charge with loss of electrons.

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3 years ago

A wire carries a steady current of 2.60 A. A straight section of the wire is 0.750 m long and lies along the x axis within a uni

ad-work [718]

Answer:

The magnetic force on the section of wire is $-2.925\hat{j}\ N$ .

Explanation:

Given that,

Current $I = 2.60\hat{i}\ A$

Length = 0.750 m

Magnetic field $B = 1.50\hat{k}\ T$

We need to calculate the magnetic force on the section of wire

Using formula of magnetic force

$\vec{F}=l\vec{I}\times\vec{B}$

$\vec{F}=0.750\times2.60\hat{i}\times1.50\hat{k}$

Since, $\hat{i}\times\hat{k}=-\hat{j}$

$\vec{F}=-2.925\hat{j}\ N$

Hence, The magnetic force on the section of wire is $-2.925\hat{j}\ N$ .

7 0

2 years ago

At an amusement park there is a ride in which cylindrically shaped chambers spin around a central axis. People sit in seats faci

Klio2033 [76]

Answer:

The radius of a chamber is 2.36 meters.

Explanation:

Given that,

The outer wall moves at a speed of 2.72 m/s.

Mass of the person, m = 75.1 kg

The person feels a force of 235 N force pressing against his back. The force acting on the person is centripetal force. It is given by the below formula :

$F=\dfrac{mv^2}{r}$

r is the radius of a chamber

$r=\dfrac{mv^2}{F}$

$r=\dfrac{75.1\times (2.72)^2}{235}$

r = 2.36 meters

So, the radius of a chamber is 2.36 meters. Hence, this is the required solution.

7 0

2 years ago