because it is mostly sunny there
It would be 35.8 Calories or calories. Not sure about that part. Hope this helps though.
Answer:
I can't draw diagrams on this web site but I can do with numbers I think. So an electron is moved from n = 1 to n = 5. I'm assuming I've interpreted the problem correctly; if not you will need to make a correction. I'm assuming that you know the electron in the n = 1 state is the ground state so the 4th exited state moves it to the n = 5 level.
n = 5 4th excited state
n = 4 3rd excited state
n = 3 2nd excited state
n = 2 1st excited state
n = 1 ground state
Here are the possible spectral lines.
n = 5 to 4, n = 5 to 3, n = 5 to 2, n = 5 to 1 or 4 lines.
n = 4 to 3, 4 to 2, 4 to 1 = 3 lines
n = 3 to 2, 3 to 1 = 2 lines
n = 2 to 1 = 1 line. Add 'em up. I get 10.
b. The Lyman series is from whatever to n = 1. Count the above that end in n = 1.
c.The E for any level is -21.8E-19 Joules/n^2
To find the E for any transition (delta E) take E for upper n and subtract from the E for the lower n and that gives you delta E for the transition.
So for n = 5 to n = 1, use -Efor 5 -(-Efor 1) = + something which I'll leave for you. You could convert that to wavelength in meters with delta E = hc/wavelength. You might want to try it for the Balmer series (n ending in n = 2). I think the red line is about 650 nm.
Explanation:
Answer:
The rate of change of the temperature is 0.0365 Kelvin per minute.
Explanation:
<u>Step 1</u>: Given data
ideal gas law: P*V = n*R*T
with P= pressure of the gas ( in atm) = 9.0 atm
with V= volume of the gass (in L) =12L
with n = number of moles = 10 moles
R = gas constant = 0.0821 L*atm* K^−1*mo^−1
T = temperature = TO BE DETERMINED
The volume decreases with a rate of 0.17L/min = dV/dT = -0.17
The pressure increases at a rate of 0.13atm/min = dP/dT
<u>Step 2:</u> The ideal gas law
P * [dV/dT] + V * [dP/dT] = nR * dT/dt
9 atm * (-0.17L/min) + 12L * 0.13atm/min = 10 moles * 0.0821 L*atm* K^−1*mo^−1 *dT/dt
0.03 = 0.821 * dT/dt
dT/dt = 0.03/0.821
dT/dt = 0.0365
Since the gas constant is expressed in Kelvin and not in °C, this means that <u>the rate of chagnge of the temperature is 0.0365 Kelvin per 1 minute.</u>
