Hi!
I think the answer is Brainstem. I hope this helps! :)
Answer:
1/6 m/s^2 ( about 1/6th gravity of Earth ( 9.81 m/s^2)
Explanation:
Displacement = yo + vo t - 1/2 a t^2
- 3.2 = 0 + 0 - 1/2 a(2.0)^2
- 3.2 = -2a
a = 3.2 / 2 = 1.6 m/s^2
Answer:
t = 6 [s]
Explanation:
In order to solve this problem we must first use this equation of kinematics.

where:
Vf = final velocity = 0 (the car comes to rest)
Vo = initial velocity = 72 [km/h]
a = acceleration [m/s²]
x = distance = 60 [m]
First we must convert the velocity from kilometers per hour to meters per second.
![72 [\frac{km}{h}]*\frac{1000m}{1km} *\frac{1h}{3600s} =20 [m/s]](https://tex.z-dn.net/?f=72%20%5B%5Cfrac%7Bkm%7D%7Bh%7D%5D%2A%5Cfrac%7B1000m%7D%7B1km%7D%20%2A%5Cfrac%7B1h%7D%7B3600s%7D%20%3D20%20%5Bm%2Fs%5D)
![0=(20)^{2} -2*a*60\\400 = 120*a\\a=3.33[m/s^{2} ]](https://tex.z-dn.net/?f=0%3D%2820%29%5E%7B2%7D%20-2%2Aa%2A60%5C%5C400%20%3D%20120%2Aa%5C%5Ca%3D3.33%5Bm%2Fs%5E%7B2%7D%20%5D)
Now using this other equation of kinematics.

0 = 20-3.33*t
t = 6[s]
Answer:
b) Betelgeuse would be
times brighter than Sirius
c) Since Betelgeuse brightness from Earth compared to the Sun is
the statement saying that it would be like a second Sun is incorrect
Explanation:
The start brightness is related to it luminosity thought the following equation:
(1)
where
is the brightness,
is the star luminosity and
, the distance from the star to the point where the brightness is calculated (measured). Thus:
b)
and
where
is the Sun luminosity (
) but we don't need to know this value for solving the problem.
is light years.
Finding the ratio between the two brightness we get:

c) we can do the same as in b) but we need to know the distance from the Sun to the Earth, which is
. Then

Notice that since the star luminosities are given with respect to the Sun luminosity we don't need to use any value a simple states the Sun luminosity as the unit, i.e 1. From this result, it is clear that when Betelgeuse explodes it won't be like having a second Sun, it brightness will be 5 orders of magnitude smaller that our Sun brightness.
Answer:
1. MOON has the greatest influence over the tides
2. Ocean currents can be caused by wind, density differences in water masses caused by temperature and salinity variations, gravity, and events such as earthquakes or storms.
Explanation: