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Scorpion4ik [409]
3 years ago
9

If an object's mass increases, its------------------------- can be increased

Physics
1 answer:
otez555 [7]3 years ago
7 0

Answer:

both kinetic energy and potential energy

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The first three inches of the spinal cord is called the
pantera1 [17]
Hi!
I think the answer is Brainstem. I hope this helps! :)
8 0
3 years ago
An astronaut is on the moon. He drops a hammer from a height of 3.2metres and it takes 2.0 seconds to reach the lunar landscape.
Anvisha [2.4K]

Answer:

1/6 m/s^2      ( about 1/6th gravity of Earth ( 9.81 m/s^2)

Explanation:

Displacement =  yo  +  vo t  - 1/2 a t^2

      -  3.2          = 0     +  0     - 1/2 a(2.0)^2

      -     3.2       =                -2a

             a = 3.2 / 2 = 1.6 m/s^2

6 0
2 years ago
Attached here is the question:
ICE Princess25 [194]

Answer:

t = 6 [s]

Explanation:

In order to solve this problem we must first use this equation of kinematics.

v_{f}^{2}=v_{o}^{2} +2*a*x

where:

Vf = final velocity = 0 (the car comes to rest)

Vo = initial velocity = 72 [km/h]

a = acceleration [m/s²]

x = distance = 60 [m]

First we must convert the velocity from kilometers per hour to meters per second.

72 [\frac{km}{h}]*\frac{1000m}{1km} *\frac{1h}{3600s} =20 [m/s]

0=(20)^{2} -2*a*60\\400 = 120*a\\a=3.33[m/s^{2} ]

Now using this other equation of kinematics.

v_{f}=v_{o}-a*t

0 = 20-3.33*t

t = 6[s]

5 0
3 years ago
b) The distance of the red supergiant Betelgeuse is approximately 427 light years. If it were to explode as a supernova, it woul
Nat2105 [25]

Answer:

b) Betelgeuse would be \approx 1.43 \cdot 10^{6} times brighter than Sirius

c) Since Betelgeuse brightness from Earth compared to the Sun is \approx 1.37 \cdot 10^{-5} } the statement saying that it would be like a second Sun is incorrect

Explanation:

The start brightness is related to it luminosity thought the following equation:

B = \displaystyle{\frac{L}{4\pi d^2}} (1)

where B is the brightness, L is the star luminosity and d, the distance from the star to the point where the brightness is calculated (measured). Thus:

b) B_{Betelgeuse} = \displaystyle{\frac{10^{10}L_{Sun}}{4\pi (427\ ly)^2}} and B_{Sirius} = \displaystyle{\frac{26L_{Sun}}{4\pi (26\ ly)^2}} where L_{Sun} is the Sun luminosity (3.9 x 10^{26} W) but we don't need to know this value for solving the problem. ly is light years.

Finding the ratio between the two brightness we get:

\displaystyle{\frac{B_{Betelgeuse}}{B_{Sirius}}=\frac{10^{10}L_{Sun}}{4\pi (427\ ly)^2} \times \frac{4\pi (26\ ly)^2}{26L_{Sun}} \approx 1.43 \cdot 10^{6} }

c) we can do the same as in b) but we need to know the distance from the Sun to the Earth, which is 1.581 \cdot 10^{-5}\ ly. Then

\displaystyle{\frac{B_{Betelgeuse}}{B_{Sun}}=\frac{10^{10}L_{Sun}}{4\pi (427\ ly)^2} \times \frac{4\pi (1.581\cdot 10^{-5}\ ly)^2}{1\ L_{Sun}} \approx 1.37 \cdot 10^{-5} }

Notice that since the star luminosities are given with respect to the Sun luminosity we don't need to use any value a simple states the Sun luminosity as the unit, i.e 1. From this result, it is clear that when Betelgeuse explodes it won't be like having a second Sun, it brightness will be 5 orders of magnitude smaller that our Sun brightness.

4 0
3 years ago
Will give brainliest! describe density currents and the major factors that cause them in 6 sentences
lana66690 [7]

Answer:

1. MOON has the greatest influence over the tides

2. Ocean currents can be caused by wind, density differences in water masses caused by temperature and salinity variations, gravity, and events such as earthquakes or storms.

Explanation:

5 0
2 years ago
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