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charle [14.2K]
3 years ago
10

The frequency of which type of eletromagtic wave i just higher than that of visible light

Physics
2 answers:
Gwar [14]3 years ago
7 0

Hello, Your hero is here and that's The Human Spider!


Answer: Electromagnetic waves with wavelengths just shorter than those of visible light; Ultraviolet rays carry out more energy than visible light because it has a higher frequency. Electromagnetic Waves with wavelengths just shorter than those of ultraviolet rays; X-Rays can penetrate through most matter.



Note: If you loved this answer why not mark brainliest.


~

Merry Christmas from

Your friendly neighborhood Human Spider!!

yawa3891 [41]3 years ago
3 0

visible light goes from red to violet in increasing frequencies. so just higher than visible light is the <u>ultra-violet</u> light/electromagnetic wave.

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DedPeter [7]

1. Since the body is thrown vertically upward, the only force acting on it as it rises and falls is gravity, which causes a constant downward acceleration with magnitude g = 9.8 m/s². Because this acceleration is constant, we can use the formula

v² - u² = 2a ∆x

where

u = initial speed

v = final speed

a = acceleration

∆x = displacement

At its maximum height, some distance y above the point where the body is launched, the body has zero velocity, so

0² - (20 m/s)² = 2 (-9.8 m/s²) y

Solve for y :

y = (20 m/s)² / (2 (9.8 m/s²)) ≈ 20.4 m

2. Relative to the ground, the body's maximum height is 60 m + 20.4 m ≈ 80.4 m.

3. At any time t ≥ 0, the body's vertical velocity is given by

v = 20 m/s - gt

At the highest point, we have

0 = 20 m/s - (9.8 m/s²) t

and solving for t gives

t = (20 m/s) / (9.8 m/s²) ≈ 2.04 s

4. The body's height y above the ground at any time t ≥ 0 is given by

y = 60 m + (20 m/s) t - 1/2 gt²

Solve for t when y = 0 :

0 = 60 m + (20 m/s) t - 1/2 (9.8 m/s²) t²

Using the quadratic formula,

t = (-b + √(b² - 4ac)) / (2a)

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t ≈ 6.09 s

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3 years ago
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dedylja [7]

Answer:

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Substituting into the equation, we have;

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