Answer:
e) None of these is true
Explanation:
Given that
Temperature = 0 K
We know that relationship between kelvin and Farenheit scale
Now by putting the values
So F= - 459.67°F
So we can say that 0 K is equal to - 459.67°F.
So the our option e is correct.
Answer:
option C
Explanation:
The correct answer is option C
When the driver takes the sharp right turn the door will exert rightward pressure on the driver.
When the driver takes the sudden right turn the tendency of the body is to be in the straight line by the vehicle moves in the circular path so, as the vehicle turns it applies a rightward force on you.
The pushing of the door to you because of the centripetal force acting on the car due to sudden sharp turn.
Answer: a) 0.04kW = 40W
b) 0.05
Explanation:
A)
Thermal efficiency of the power cycle = Input / output
Input = 10 kW + 14,400 kJ/min = 10 kW + 14,400 kJ/(60s) = 10 kW + 14,400/60 kW.
Output = 10 kW
Thermal Efficiency = Output / Input = 10kW / 250kW = 0.04KW = 40W
B)
Maximum Thermal Efficiency of the power cycle = 1 - T1/T2
Where T1 = 285kelvin
And T2 = 300kelvin
Maximum Thermal Efficiency = 1 - T1/T2 = 1 - 285/300 = 0.05
Proton I think if I remember right
The centripetal acceleration is 27.692 kg m / s^2.
The mass of the ball is 7.94 kg.
<u>Explanation:</u>
- The curved path of an object experience a force known as centripetal force. Its direction is always pointing to the motion of the body towards the center of curvature of the path.
centripetal force Fc = (mass * square of velocity) / radius
where m represents mass in kg
v represents velocity
r represents radius in a meter.
- The acceleration experienced in uniform circular motion is called as centripetal acceleration.It always points toward the center of rotation and is perpendicular to the linear velocity.
- centripetal acceleration = v^2 / r
= (6 * 6) / 1.3
= 27.692 kg m / s^2.
The mass of the ball is found by using the centripetal force formula,
- centripetal force Fc = m v^2 / r
m = (F * r) / v^2
= (220 * 1.3) / 36
mass of the ball m = 7.94 kg.
