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Nadusha1986 [10]
3 years ago
10

If the object on the right gained mass so that it had as much mass as the

Chemistry
1 answer:
Viefleur [7K]3 years ago
4 0

A) It would increase.

Explanation:

The gravitational force between the two masses will increase.

This is in compliance with universal law of gravitation proposed by newton.

Newton's law of universal gravitation states that "the gravitational force of attraction between two masses is directly proportional to the product of the masses and inversely proportional to the square of the distance them".

From law, we can establish that the gravitational force is directly proportional to the product of the masses between two bodies.

The higher the mass, the higher the gravitational force.

learn more:

Universal gravitational law brainly.com/question/1724648

#learnwithBrainly

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A geochemist in the field takes a 36.0 mL sample of water from a rock pool lined with crystals of a certain mineral compound X.
Ostrovityanka [42]

Answer:

The solubility of X in water at 17°C is 0.110 g/mL.

Explanation:

The water of a rock pool lined with mineral crystals is a <em>saturated solution</em> of said mineral, this means the concentration of X in those 36 mL is the solubility of compound X in water at 17 °C.

  • This means<u> it is possible to calculate said solubility</u>.

The dilution of the sample is not relevant, nor is that 500 mL volume. What's important is that 3.96 g of X form a saturated solution with 36.0 mL of water, so the solubility is:

  • 3.96 g / 36.0 mL = 0.110 g/mL
4 0
3 years ago
Chemistry help please
Galina-37 [17]

Answer:

The reaction isn't yet at equilibrium. The overall reaction will continue to move in the direction of the products.

Assumption: this system is currently at \rm 900^{\circ}C.

Explanation:

One way to tell whether a system is at its equilibrium is to compare its reaction quotient Q with the equilibrium constant K_c of the reaction.

The equation for Q is quite similar to that for K_c. The difference between the two is that K_c requires equilibrium concentrations, while Q can be calculated even when the system is on its way to equilibrium.

For this reaction,

\displaystyle Q = \rm \frac{[CS_2]\cdot [H_2]^{4}}{[CH_4]\cdot [H_2S]^{2}}.

Given these concentrations,

\displaystyle Q = \rm \frac{[CS_2]\cdot [H_2]^{4}}{[CH_4]\cdot [H_2S]^{2}} =\frac{1.51\times (1.08)^{4}}{1.15\times (1.20)^{2}} \approx 1.72.

The question states that at \rm 900^{\circ}C, K_c = 3.59. Assume that currently this system is also at \rm 900^{\circ}C. (The two temperatures need to be the same since the value of K_c depends on the temperature.)

It turns out that Q = K_c. What does this mean?

  • First, the system isn't at equilibrium.
  • Second, if there's no external changes, the system will continue to move towards the equilibrium. Temperature might change. However, eventually Q will be equal to K_c, and the system will achieve equilibrium.

In which direction will the system move? At this moment, Q < K_c. As time proceeds, the value of Q will increase so that it could become equal to K_c. Recall that Q is fraction.  

\displaystyle Q = \rm \frac{[CS_2]\cdot [H_2]^{4}}{[CH_4]\cdot [H_2S]^{2}}

When the value of Q increases, either its numerator becomes larger or its denominator becomes smaller, or both will happen at the same time. However,

  • Concentrations on the numerator of Q are those of the products;
  • Concentrations on the denominator of Q are those of the reactants.

As time proceeds,

  • the concentration of the products will increase, while
  • the concentration of the reactants will decrease.

In other words, the equilibrium will move towards the products.

3 0
4 years ago
What does Avagardo's Law state?
qaws [65]

Answer:

Avogadro's law, a statement that under the same conditions of temperature and pressure, equal volumes of different gases contain an equal number of molecules.

7 0
3 years ago
Read 2 more answers
A sample of gas has an initial volume of 3.00 L and an initial pressure of 2.14 atm. If the volume expands to 8.15 L, what is th
Alla [95]

Answer:

The final pressure is 0.788 atm (option b).

Explanation:

Boyle's law says that the volume occupied by a given gaseous mass at constant temperature is inversely proportional to pressure. That is: if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases. This is expressed mathematically as the product of pressure times volume equal to a constant value:

P*V=k

Assuming a certain volume of gas V1 that is at a pressure P1 at the beginning of the experiment, by varying the volume of gas to a new value V2, then the pressure will change to P2, and it will be fulfilled:

P1*V1=P2*V2

In this case:

  • P1= 2.14 atm
  • V1= 3 L
  • P2= ?
  • V2= 8.15 L

Replacing:

2.14 atm*3 L= P2* 8.15 L

Solving:

\frac{2.14 atm*3 L}{8.15 L} =P2

0.788 atm= P2

<u><em>The final pressure is 0.788 atm (option b).</em></u>

6 0
3 years ago
Unlike gases, the behavior of liquids and solids cannot be described by a set of laws that can be applied regardless of the iden
Tresset [83]

Answer:

a. True

Explanation:

The gases that we study are governed by different laws of physics. Gases behaves according to some given set of laws like the Universal gas laws, Boyles law, Charles law, Gay Lussac's law and many more.

But we do not see a definite pattern or rule when we study solids or liquids. The behavior of the solids and liquids are not described by the set of laws which are applied regardless of the identity of the substance.

6 0
3 years ago
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