Answer:
The second trumpeter will be playing at frequency = 515 Hz
Explanation: Given that the note sounds lower and they can hear 20 beats in 4.0 s.
Beat frequency = 20/4 = 5 Hz
Beat frequency = F2 - F1
5 = 520 - F1
F1 = 520 - 5
F1 = 515 Hz
Since the note sound lower, the second trumpeter will be playing at 515 Hz frequency
In scientific terms, ultrasound is a sound pressure, cyclic in nature, that has a greater frequency than the limit at the top of human hearing capabilities. What this means is that an ultrasonic sound can’t be heard by the human ear because their frequency is too high for our ears to pick up. In healthy young adults, this upper hearing capability is an average of 20 kilohertz. Ultrasound has many applications in several fields. Perhaps the best known application for ultrasound is sonography. This is where medical staff use the high pitched noise to produce a picture of a fetus while in the mother’s womb. Another use however, doesn’t directly concern humans at all. Bats use the high pitched noises to see in the dark and get an accurate reading on their preys internal structure. A popular belief is that an ultrasonic sound has the ability to turn the locking mechanism in a door lock, as demonstrated on some spy movies. On the opposite side of this are infrasonic sounds. These are noises with a frequency less than the lowest level of human hearing capabilities is 20 hertz. It is possible for humans to perceive infrasonic sounds, but only if the air pressure is sufficient. Although the war is the main tool for hearing these low sounds, it is possible for other parts of the body to “feel them”. Infrasound can be used to send signals in the army to special machines that can pick them up. These can be used to transmit vital data. Animals are able to pick up some low infrasonic noises which warn them of natural disasters before they happen, generally earthquakes and tsunamis.
I hope some of this information I gave you can help you. I came up with everything myself to help you.
Answer:
20.6 N
Explanation:
Friction equals normal force times coefficient of friction.
F = Fn μ
On level ground, normal force equal weight.
Fn = W
Therefore:
F = W μ
F = (685 N) (0.0300)
F = 20.6 N
Answer:
Explanation:
Given:
Initial mass of isotope (m₀) = 20 g
Half life of the isotope 
= (ln 4) years
The general form for the radioactive decay of a radioactive isotope is given as:
Where,
So, the equation is: 
At half-life, the mass is reduced to half of the initial value.
So, at 
. Plug in these values and solve for 'k'. This gives,
Hence, the equation for the mass remaining is given as:
