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Papessa [141]
3 years ago
15

A 0.5-kilogram ball is thrown vertically upward with an initial kinetic energy of 25 joules. Ap-proximately how high will the ba

ll rise?
Physics
1 answer:
tatuchka [14]3 years ago
4 0
It's gravitational potential energy at the top will roughly equal it's kinetic energy when it was released (a little is lost to air resistance).  Note this will assume the release point is zero potential energy.  (we are free to define it that way, just letting you know).  Gravitational potential energy is mgh.
mgh=25J
h=25J/(0.5kg x 9.81m/s^2) = 5.097m
So it goes about 5.1 meters above the point where it was released
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What is the pressure exerted by a column of fresh water 10m high<br>(p=1000kg/m3 and g=10m/s)​
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<u>1000</u><u>0</u><u>0</u><u> </u><u>Pa</u>

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A parallel plate capacitor creates a uniform electric field of and its plates are separated by . A proton is placed at rest next
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Complete Question

A parallel plate capacitor creates a uniform electric field of 5 x 10^4 N/C and its plates are separated by 2 x 10^{-3}'m. A proton is placed at rest next to the positive plate and then released and moves toward the negative plate. When the proton arrives at the negative plate, what is its speed?

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V=1.4*10^5m/s

Explanation:

From the question we are told that:

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