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Otrada [13]
3 years ago
7

A person standing a certain distance from an airplane with four equally noisy jet engines is experiencing a sound level of 145 d

B . What sound level would this person experience if the captain shut down all but one engine?
Physics
1 answer:
Katyanochek1 [597]3 years ago
5 0

Answer:

The sound level is 138.97 dB.

Explanation:

Given that,

Sound level L= 145 dB

We need to calculate the intensity

Using formula of sound intensity

L=10\log(\dfrac{I}{I_{0}})

Put the value into the formula

145=10\log(\dfrac{I}{I_{0}})

\log(\dfrac{I}{I_{0}})=\dfrac{145}{10}

\log(\dfrac{I}{I_{0}})=14.5

\dfrac{I}{I_{0}}=10^{14.5}

I=10^{14.5}\times I_{0}

I=10^{14.5}\times10^{-12}

I=316.2

We need to calculate the noise of one engine

Using formula of intensity

I'=\dfrac{I}{4}

Put the value into the formula

I'=\dfrac{316.2}{4}

I'=79.05

We need to calculate the intensity level due to one engine

Using formula of sound intensity

L'=10\log(\dfrac{I'}{I_{0}})

L'=10\log(\dfrac{79.05}{10^{-12}})

L'=138.97\ dB

Hence, The sound level is 138.97 dB

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Answer:

0.786 Hz, 1.572 Hz, 2.358 Hz, 3.144 Hz

Explanation:

The fundamental frequency of a standing wave on a string is given by

f=\frac{1}{2L}\sqrt{\frac{T}{\mu}}

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For the string in the problem,

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