Question

How much time does it take the satellite to complete one revolution? Scientists want to place a 3300 kg satellite in orbit around Mars. They plan to have the satellite orbit a distance equal to 2.2 times the radius of Mars above the surface of the planet. Here is some information that will help solve this problem:

Answer 1

Answer:

$T = 5.45 h$

Explanation:

As we know that time period of one revolution around Mars is given as

$T = 2\pi\sqrt{\frac{r^3}{GM}}$

here we know that

$r = 2.2 R$

here we know that radius of Mars is given as

$R = 3.396 \times 10^6 m$

mass of Mars is given as

$M = 6.42 \times 10^{23} kg$

now we have

$T = 2\pi \sqrt{\frac{(2.2\times 3.396 \times 10^6)^3}{(6.67 \times 10^{-11})(6.42\times 10^{23})}}$

$T = 19608 s$

$T = 5.45 h$