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weqwewe [10]
3 years ago
9

Please...physics rotation questions

Physics
1 answer:
kari74 [83]3 years ago
7 0
1st Question:
There are 4 formulas involving angular velocity:
For the first question, we are given the initial angular velocity (ωo), final angular velocity (ωf), and the amount of time. The question is asking us to find the angular acceleration (α).
Knowing this information, we can use w=wo+ \alpha t
Lets plug in the values given in the question:
w=wo+ \alpha t
123  \frac{rad}{sec}  = 11  \frac{rad}{sec} + (4.5 sec) \alpha
Now we just solve for \alpha
123 \frac{rad}{sec} = 11 \frac{rad}{sec} + (4.5 sec) \alpha
Subtract 11 from each side
112 \frac{rad}{sec} = (4.5 sec) \alpha
Divide each side by 4.5 sec. 
\alpha = 24.89  \frac{rad}{sec^{2} }
----------------------------------------------------------
2nd Question:
For the second question, we want to find the change in distance (which is AKA radians). So we know we would need to use either the 1st, 3rd or the 4th equation. We are given time (t=45 s), the initial velocity (wo=0 rad/s), and the final velocity (w=245 rad/s). Since the 4th equation doesn't have time, and the 3rd equation has angular acceleration (which we weren't given), we know we will need to use the 1st equation. 
theta=wt (in which w is the change in velocity. Which for this case, would be 245-0)
theta=(245 rad/s)(45 s) 
Simplify
theta=11025 rad 

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alexandr1967 [171]

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The motion of an object undergoing constant acceleration can be modeled by the kinematic equations. One such equation is xf=xi+v
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a = 1.72 m/s²

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The given kinematic equation is the 2nd equation of motion. The equation is as follows:

xf = xi + (Vi)(t) + (1/2)(a)t²

where,

xf = the final position =  5000 m

xi = the initial position = 1000 m

Vi = the initial velocity = 15 m/s

t = the time taken = 60 s

a = acceleration = ?

Therefore,

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5000 m - 1900 m = a(1800 s²)

a(1800 s²) = 3100 m

a = 3100 m/1800 s²

<u>a = 1.72 m/s²</u>

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