1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
weqwewe [10]
3 years ago
9

Please...physics rotation questions

Physics
1 answer:
kari74 [83]3 years ago
7 0
1st Question:
There are 4 formulas involving angular velocity:
For the first question, we are given the initial angular velocity (ωo), final angular velocity (ωf), and the amount of time. The question is asking us to find the angular acceleration (α).
Knowing this information, we can use w=wo+ \alpha t
Lets plug in the values given in the question:
w=wo+ \alpha t
123  \frac{rad}{sec}  = 11  \frac{rad}{sec} + (4.5 sec) \alpha
Now we just solve for \alpha
123 \frac{rad}{sec} = 11 \frac{rad}{sec} + (4.5 sec) \alpha
Subtract 11 from each side
112 \frac{rad}{sec} = (4.5 sec) \alpha
Divide each side by 4.5 sec. 
\alpha = 24.89  \frac{rad}{sec^{2} }
----------------------------------------------------------
2nd Question:
For the second question, we want to find the change in distance (which is AKA radians). So we know we would need to use either the 1st, 3rd or the 4th equation. We are given time (t=45 s), the initial velocity (wo=0 rad/s), and the final velocity (w=245 rad/s). Since the 4th equation doesn't have time, and the 3rd equation has angular acceleration (which we weren't given), we know we will need to use the 1st equation. 
theta=wt (in which w is the change in velocity. Which for this case, would be 245-0)
theta=(245 rad/s)(45 s) 
Simplify
theta=11025 rad 

You might be interested in
the distance between any two bodies is 10 M and the gravitational force between them is 3.2×10-⁹m. if the mass of one object is
cluponka [151]

Answer:

0.8 x 10^-9 kg

Explanation:

Given,

Distance ( R ) = 10 m

Force ( F ) = 3.2 x 10^-9 N

Mass ( m1 ) = 40 kg

To find : Mass ( m2 ) = ?

Formula : -

F = m1.m2 / R^2

m2 = FR^2 / m1

= 3.2 x 10^-9 x 10 / 40

= 3.2 x 10^-9 / 4

= ( 3.2 / 4 ) x 10^-9

m2 = 0.8 x 10^-9 kg

3 0
3 years ago
2. An 873 kg dragster accelerates at a rate of 44.6 m/s during a race.
Ira Lisetskai [31]

Answer:

<h3>38,673.9N</h3>

Explanation:

According to newton's second law:

Force = mass * acceleration

Given

Mass = 873kg

acceleration = 44.66m/s²

Magnitude of the force is expressed as;

F = ma

F = 873 * 44.6

F = 38,673.9N

<em>Hence the magnitude of the net force exerted on the dragster during this time is 38,673.9N</em>

8 0
2 years ago
In comparing sunspots to other areas of the sun's surface one can say that sunspots are...?
taurus [48]

Answer:

D. Cooler

Explanation:

The Sun's surface has a temperature ranging from 6 000 Kelvin, thus it is very hot. The radioactive reaction in the core of the Sun is a nuclear fusion reaction. This reaction ensures continuous release of high energy from the surface of the Sun.

But during the reaction, some parts becomes cooler than other parts on its surface. Which is due to the release of high amount of energy into space. The Sun's spot can be found in the cooler part of the Sun.

8 0
2 years ago
The atmosphere protects us from all of the following except Meteorites The sun's rays Pollution Wind
denis23 [38]
Meteorites is the answer

6 0
3 years ago
A police car is driving down the street with it's siren on. You are standing still on the sidewalk beside the street. If the fre
AleksandrR [38]

Answer:

A) 1568.60 Hz

B) 1437.15 Hz

Explanation:

This change is frequency happens due to doppler effect

The Doppler effect is the change in frequency of a wave in relation to an observer who is moving relative to the wave source

f_(observed)=\frac{(c+-V_r)}{(C+-V_s)} *f_(emmited)\\

where

C = the propagation speed of waves in the medium;

Vr= is the speed of the receiver relative to the medium,(added to C, if the receiver is moving towards the source, subtracted if the receiver is moving away from the source;

Vs= the speed of the source relative to the medium, added to C, if the source is moving away from the receiver, subtracted if the source is moving towards the receiver.

A) Here the Source is moving towards the receiver(C-Vs)

and the receiver is standing still (Vr=0) therefore the observed frequency should get higher

f_(observed)=\frac{C}{C-V_s} *f_(emmited)\\=\frac{343}{343-15}*1500\\ =1568.60 Hz

B)Here the Source is moving away the receiver(C+Vs)

and the receiver is still not moving (Vr=0) therefore the observed frequency should be lesser

f_(observed)=\frac{C}{C+V_s} *f_(emmited)\\=\frac{343}{343+15}*1500\\ =1437.15 Hz

3 0
3 years ago
Other questions:
  • "As you sit in a fishing boat, you notice that 12 waves pass the boat every 45 s. If the distance from one crest to the next is
    6·1 answer
  • Can Someone help me answer the question?
    14·1 answer
  • 1 kg of aluminum requires 887 J (Joule) to raise its temperature by 1 K (Kelvin). The specific heat of aluminum is expressed as
    14·1 answer
  • Which are the simplest pure substances that cannot be broken down into any other substances
    10·1 answer
  • If you were an Astronaut in the middle of the near side of the moon during a full moon, how would the ground around you look? Ho
    8·1 answer
  • Dynamics Newton's 1st &amp; 2nd Laws
    13·1 answer
  • Give the SI unit. For physics
    12·1 answer
  • ____________ is an individual sport that helps develop your hand-eye coordination.
    9·1 answer
  • A process generates 250 watts of useful energy and 600 watts of waste energy. WhT is the efficiency of the process?
    9·1 answer
  • 15 POINTS!!! QUICK PLEASE
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!