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Scorpion4ik [409]
3 years ago
7

A 0.500 g sample of He at STP has a volume that is one-half that of an unknown pure gas also at STP. The unknown pure gas sample

has a mass of 36.5 g. What is the molar mass of the unknown gas?
Chemistry
1 answer:
Anuta_ua [19.1K]3 years ago
4 0

Answer:

Molar mass of the unknown gas: 146 g /mol

Explanation:

At STP, any "ideal" gas is contained in a volume of 22.4L. This situation, for 1 mol of gas. In this case we have:

0.5 g / 4 g/mol = 0.125 moles of He

These amount of He occupies 0.125 mol . 22.4L / 1 mol = 2.8 L so the double of volume will be occupied by the unkown gas.

22.4 L / 1 mol = (2.8 L . 2) / x moles

22.4L / 1 mol = 5.6 L / x mol

x mol = 5.6L / 22.4L → 0.25 moles

To determine the molar mass of the unknown gas → 36.5 g / 0.25 mol = 146 g /mol

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scandium47 has a half-life of 35s. suppose you have a 45g sample of scadium 47 how much of the sample remains unchanged after 14
Mars2501 [29]

 The much  of the sample that would remain  unchanged  after 140 seconds is 2.813 g

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Half life  is time taken for the quantity  to reduce  to half its original value.

if the half life  for Scandium  is 35 sec, then the number  of half life in 140 seconds

=140 sec/ 35 s = 4 half life

Therefore 45 g after first half life = 45 x1/2 =22.5 g

               22.5 g after second half life = 22.5 x 1/2 =11.25 g

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3 years ago
How much carbon would be needed to make 8.8g of carbon dioxide?<br>​
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The calculation for such a question can be achieved via Avogadro hypothesis

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=> 1g = (6.023/44) ※10^23 CO2 molecules

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Thus there r 1.2046 ※10^23 molecules of CO2 in 8.80g

if u need to calculate no. of carbon atoms then multiply result by 1 and if u need no of oxygen atoms in 8.80g of co2 then multiply the result by 2 ….
7 0
2 years ago
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