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Scorpion4ik [409]
2 years ago
7

A 0.500 g sample of He at STP has a volume that is one-half that of an unknown pure gas also at STP. The unknown pure gas sample

has a mass of 36.5 g. What is the molar mass of the unknown gas?
Chemistry
1 answer:
Anuta_ua [19.1K]2 years ago
4 0

Answer:

Molar mass of the unknown gas: 146 g /mol

Explanation:

At STP, any "ideal" gas is contained in a volume of 22.4L. This situation, for 1 mol of gas. In this case we have:

0.5 g / 4 g/mol = 0.125 moles of He

These amount of He occupies 0.125 mol . 22.4L / 1 mol = 2.8 L so the double of volume will be occupied by the unkown gas.

22.4 L / 1 mol = (2.8 L . 2) / x moles

22.4L / 1 mol = 5.6 L / x mol

x mol = 5.6L / 22.4L → 0.25 moles

To determine the molar mass of the unknown gas → 36.5 g / 0.25 mol = 146 g /mol

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If an acid or alkali is diluted by a factor of 10, what effect will this have on its pH?
Alisiya [41]

Answer: When an acidic solution is diluted with water the concentration of H + ions decreases and the pH of the solution increases towards 7.

Explanation:

5 0
2 years ago
If 500ml of H₂ gas at 600mmHg and 400ml of CO₂ gas at 700mmHg are mixed in a 1 lit vessel, find the total pressure of mixture of
seraphim [82]

Answer:

Total pressure increased

Explanation:

When gas C is added in the vessel then number of mole increases and number of collision depends on the number of molecules present in the vessel and on adding gas C ,mole also increases hence  number of collision increases therefore pressure also increases because number of collision increases.

Total pressure increases.

6 0
2 years ago
A 4.0 L balloon has a pressure of 406 kPa. When the pressure increases to 2,030 kPa, what is the volume? *
elena-14-01-66 [18.8K]

The new volume when pressure increases to 2,030 kPa is 0.8L

BOYLE'S LAW:

The new volume of a gas can be calculated using Boyle's law equation:

P1V1 = P2V2

Where;

  1. P1 = initial pressure (kPa)
  2. P2 = final pressure (kPa)
  3. V1 = initial volume (L)
  4. V2 = final volume (L)

According to this question, a 4.0 L balloon has a pressure of 406 kPa. When the pressure increases to 2,030 kPa, the volume is calculated as:

406 × 4 = 2030 × V2

1624 = 2030V2

V2 = 1624 ÷ 2030

V2 = 0.8L

Therefore, the new volume when pressure increases to 2,030 kPa is 0.8L.

Learn more about Boyle's law calculations at: brainly.com/question/1437490?referrer=searchResults

3 0
2 years ago
Help please i’ll give extra points
joja [24]

Answer:

okay no problem

I will give

7 0
3 years ago
What is the pH of a 3.5 x 10 to the negative 11th M H+ solution
Ghella [55]

Answer:

Explanation:

-log(3.5 * 10^-11)

= 10.4559

Be careful how you put this into your calculator. I had to use Exp to get it to work properly.

-log

(3.5 * 10 exp -11)

=

4 0
3 years ago
Read 2 more answers
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