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Step2247 [10]
3 years ago
11

A student thinks that the more protons an atom has, the more reactive it will be. Which will best disprove this student's idea?

Chemistry
2 answers:
Tema [17]3 years ago
6 0

Answer:

Compare the reactivities of lithium (Li) and Krypton (Kr)

Explanation:

Lithium has an <em>atomic number </em>of <em>3</em> while krypton has an <em>atomic number</em> of <em>36</em>. Note that <em>atomic number</em> is the <em>number of protons </em>present in an atom. It can be deduced from the above that krypton has more protons than lithium however krypton is found in the group zero of the periodic table and thus a noble gas. One of the properties of noble gases/group zero elements is that they have low reactivity because of there octet configuration/completely filled outermost shell.

However, lithium on the other hand is a member of group 1 (called alkali metals) in the periodic table. Group 1 elements are highly reactive (there members are some of the most reactive metals) because they have just one electron in there outermost shell which can be easily donated to achieve duplet/octet configuration.

Hence, Lithium (Li) with 3 protons is more reactive than krypton (Kr) with 36 protons hence disputing the student's idea.

d1i1m1o1n [39]3 years ago
3 0
I'd have to say that the best choice of the ones listed above would be the first one.
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Explanation:

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Which best describes a compound such as sodium chloride
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5 0
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How many formula units are there in 50.3 moles potassium chloride?
Alona [7]
<h3>Answer:</h3>

3.03 × 10²⁵ formula units KCl

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Unit 0</u>

  • Reading a Periodic Table
  • Writing Compounds

<u>Atomic Structure</u>

  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>Explanation:</h3>

<u>Step 1: Define</u>

50.3 mol KCl (Potassium chloride)

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

<u />\displaystyle 50.3 \ mol \ KCl(\frac{6.022 \cdot 10^{23} \ formula \ units \ KCl}{1 \ mol \ KCl} ) = 3.02907 × 10²⁵ formula units KCl

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

3.02907 × 10²⁵ formula units KCl ≈ 3.03 × 10²⁵ formula units KCl

6 0
3 years ago
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