Question

A certain metal wire has a cross-sectional area of 1.0 cm2 and a resistivity of 1.7 × 10-8 Ω ∙ m. How long would it have to be to have a resistance of 1.0 Ω?

Answer 1

Answer:

L=5882.35 m

Explanation:

Given that

Area ,A= 1 cm²

Resistivity  ,ρ = 1.7 x 10⁻⁸ Ω ∙ m

Resistance ,R= 1 Ω

Lets take length of the wire = L

$R=\rho \times \dfrac{L}{A}$

Resistivity  =ρ

Resistance =R

Area =A

Resistance =R

$L=\dfrac{R\times A}{\rho }$

Now by putting the values in the above equation get

$L=\dfrac{1\times 1\times 10^{-4}}{1.7\times 10^{-8} }\ m$

L=5882.35 m

Therefore the length of the wire will be 5882.35 m.