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LiRa [457]
3 years ago
9

The table shows results from an experiment in which objects made up of different materials are rubbed with each other. Based on

the results, what can be predicted if an object made of rubber is rubbed with an object made of glass? A) The glass object will become negatively charged, and the rubber object will remain neutral. B) The rubber object will become negatively charged, and the glass object will remain neutral. C) The glass object will become negatively charged, and the rubber object will become positively charged. D) The rubber object will become negatively charged, and the glass object will become positively charged.
Physics
1 answer:
Anna [14]3 years ago
5 0

Answer:

D) The rubber object will become negatively charged, and the glass object will become positively charged.

Explanation:

Electron affinity of rubber or glass will decide the thing that rubber will get the negative charge or the glass will get the negative charge

As we know that if the electron affinity of a given material is high then that material will not lose its electron while rubbing with some other material.

When we compare rubber and glass then we know that electron affinity of rubber is more as compare to glass.

So rubber will get negative charge when we rub it with glass

so correct answer will be

D) The rubber object will become negatively charged, and the glass object will become positively charged.

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I MARK BRAINLIEST, PLEASE ANSWER ASAP!!! PHYSICS 20 POINTS!!
irina [24]
The first one is C. Hope this helps!! If you need anymore help just message me and I will try to get back to you quickly and help in any way i can!
5 0
3 years ago
Read 2 more answers
A family is skating at an ice rink. The 58.2 kg mother is holding the
MariettaO [177]

Answer:

When I got this question I had to draw it out so if you have to do that, draw 3 stick figures holding hands, one representing the mother, father, and daughter. Then you write their weights on top of them and then draw an arrow pointing from the father to the mother.

Explanation:

use this formula :

a_{y} = \frac{Fdadshandy}{msys}

then you fill it in :

a_{y} = \frac{100N}{35.5kg+58.2kg}

a_{y} = \frac{100N}{93.7kg}

a_{y} = 1.0672 m/s^{2}

then you multiply that with the daughters weight :

T_{2} x= m_{2} a_{y}

T_{2} x = 35.5kg (1.0672 m/s^{2})

T_{2} x = 37.89N

and that's the answer :) : 37.89N

5 0
3 years ago
Potassium is a crucial element for the healthy operation of the human
Dovator [93]
The second one if it’s on edge
8 0
3 years ago
f your risk-aversion coefficient is A = 4 and you believe that the entire 1926–2015 period is representative of future expected
siniylev [52]

Answer:

The portfolio should invest 48.94% in equity while 51.05% in the T-bills.

Explanation:

As the complete question is not given here ,the table of data is missing which is as attached herewith.

From the maximized equation of the utility function it is evident that

Weight=\frac{E_M-r_f}{A\sigma_M^2}

For the equity, here as

  • Weight is percentage of the equity which is to be calculated
  • {E_M-r_f} is the Risk premium whose value as seen from the attached data for the period 1926-2015 is 8.30%
  • A is the risk aversion factor which is given as 4.
  • \sigma_M is the standard deviation of the portfolio which from the data for the period 1926-2015 is 20.59

By substituting values.

Weight=\frac{E_M-r_f}{A\sigma_M^2}\\Weight=\frac{8.30\%}{4(20.59\%)^2}\\Weight=0.4894 =48.94\%

So the weight of equity is 48.94%.

Now the weight of T bills is given as

Weight_{T-Bills}=1-Weight_{equity}\\Weight_{T-Bills}=1-0.4894\\Weight_{T-Bills}=0.5105=51.05\%\\

So  the weight of T-bills is 51.05%.

The portfolio should invest 48.94% in equity while 51.05% in the T-bills.

7 0
3 years ago
PRACTICE ANOTHER A cube of wood having an edge dimension of 19.7 cm and a density of 647 kg/m3 floats on water. (a) What is the
dedylja [7]

CHECK COMPLETE QUESTION

The cube of wood having an edge dimension of 19.7cm and a density of 647kg/m3 floats on water

(a) What is the distance from the horizontal top surface of the cube to the water level answer in cm

(b) What mass of lead should be placed on the cube so that the top of the cube will be just level with the water surface answer in kg

Answer:

a)6.29cm

b)2.78 kg

Explanation:

Given:

Let us calculate the volume first, we were given dimension as 19.7cm=0.197m

Volume is (0.197 meters)³ = 0.00764m³

Then we can calculate the mass as;

Given mass is 647 kg/m³ x 0.00774m³ = 4.947kg

The weight = mass × acceleration due to gravity

weight = 4.947 x 9.8 N/kg = 48.44N

By Floating we can say the the buoyancy force has to equal the weight (48.44 N) which has

which is equal to the weight of volume of the displaced water. Or the mass, the calculation is the same.

We know that density of fresh water at 20ºC is 998 kg/m³

Then we can calculate the volume of displaced water as

4.947 kg / 998 kg/m³ = 0.00496 m³

We know that the displaced water has a shape of a rectangular solid with 0.197 meters on the two horizontal dimensions, and h as the height to the surface then

V = 0.197²h = 0.00496

0.00496= 0.197²h

h = 0.1278 meters or 12.78 cm

Then the the distance exposed, would be 19.7–12.78 = 6.29 cm

b) ifthe cube is fully submerged, the volume of the displaced water is 0.00774m³

mass of displaced water is 0.00774m³ x 998 kg/m³ = 7.724 kg

Added mass is the mass of the displaced water – mass of block

= 7.724–4.947 = 2.78 kg

5 0
3 years ago
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