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LiRa [457]
4 years ago
9

The table shows results from an experiment in which objects made up of different materials are rubbed with each other. Based on

the results, what can be predicted if an object made of rubber is rubbed with an object made of glass? A) The glass object will become negatively charged, and the rubber object will remain neutral. B) The rubber object will become negatively charged, and the glass object will remain neutral. C) The glass object will become negatively charged, and the rubber object will become positively charged. D) The rubber object will become negatively charged, and the glass object will become positively charged.
Physics
1 answer:
Anna [14]4 years ago
5 0

Answer:

D) The rubber object will become negatively charged, and the glass object will become positively charged.

Explanation:

Electron affinity of rubber or glass will decide the thing that rubber will get the negative charge or the glass will get the negative charge

As we know that if the electron affinity of a given material is high then that material will not lose its electron while rubbing with some other material.

When we compare rubber and glass then we know that electron affinity of rubber is more as compare to glass.

So rubber will get negative charge when we rub it with glass

so correct answer will be

D) The rubber object will become negatively charged, and the glass object will become positively charged.

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A 34-m length of wire is stretched horizontally between two vertical posts. The wire carries a current of 68 A and experiences a
il63 [147K]

Answer:

7.28×10⁻⁵ T

Explanation:

Applying,

F = BILsin∅............. Equation 1

Where F = magnetic force, B = earth's magnetic field, I = current flowing through the wire, L = Length of the wire, ∅ = angle between the field and the wire.

make B the subject of the equation

B = F/ILsin∅.................. Equation 2

From the question,

Given: F = 0.16 N, I = 68 A, L = 34 m, ∅ = 72°

Substitute these values into equation 2

B = 0.16/(68×34×sin72°)

B = 0.16/(68×34×0.95)

B = 0.16/2196.4

B = 7.28×10⁻⁵ T

7 0
3 years ago
Help ASAP ITS DUE IN 30 MIN
Katena32 [7]

can't read it, need larger picture

5 0
4 years ago
A car of mass 1000 kg is moving at 25 m/s. It collides with a car of mass 1200 kg moving at 30 m/s. When the cars collide, they
Alinara [238K]

Answer:

The total momentum of the cars before the collision is 61,000 kg.m/s

The total momentum of the cars after the collision is 61,000 kg.m/s

The velocity of the cars after the collision is 27.727 m/s

Explanation:

Given;

mass of the first car, m₁ = 1000 kg

initial velocity of the car, u₁ = 25 m/s

mass of the second car, m₂ = 1200 kg

initial velocity of the second car, u₂ = 30 m/s

The common velocity of the cars after collision = v

The total momentum of the cars before collision is calculated as;

P₁ = m₁u₁  +  m₂u₂

P₁ = (1000 x 25)  +  (1200 x 30)

P₁ = 61,000 kg.m/s

The total momentum of the cars after collision is calculated as;

P₂ = m₁v + m₂v

where;

v    is the common velocities of the cars after collision since they stick together.

P₂ = v(m₁ + m₂)

To determine "v" apply the principle of conservation of linear momentum for inelastic collision.

m₁u₁  +  m₂u₂  = v(m₁  + m₂)

(1000 x 25)  +  (1200 x 30) = v(1000 + 1200)

61,000 = 2,200v

v = 61,000/2,200

v = 27.727 m/s

The total momentum after collsion = v(m₁ + m₂)

                                                         = 27.727(1000 + 1200)

                                                          = 61,000 kg.m/s

Thus, momentum before and after collsion are equal.

8 0
3 years ago
Use the image above to answer the following for 2 points each:
kotykmax [81]

Answer: the divergent one goes where it looks like there a crack because when you think about divergent it means dividing like seperating.(igneous rock) is where the divegent one goes.

the one that is no plate boundary is sedimentary rock and it occurs by because there is nothing there for it todo there

Explanation:

6 0
3 years ago
A proton and an electron are both accelerated to the same final speed. If λp s the de Broglie wavelength of the proton and e is
meriva

Answer:

Explanation:

The relation between the de Broglie wavelength and the momentum of the particle is given by

\lambda =\frac{h}{m\times v}

where, m is the mas of the particle and v be the velocity of the particle and h be the Plank's constant.  

So, the de broglie wavelength of proton is given by

\lambda _{p}=\frac{h}{m_{p}\times v} .... (1)

The de broglie wavelength of electron is given by

\lambda _{e}=\frac{h}{m_{e}\times v} .... (2)

Divide equation (2) by equation (1), we get

\frac{\lambda _{e}}{\lambda _{p}}=\frac{m_{p}}{m_{e}}

As the mass of proton is much more than the mass of electron, so the de broglie wavelength of electron is more than the de Broglie wavelength of proton.

5 0
4 years ago
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