Explain the difference between speed and vilocity?
1 answer:
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Answer:
L = 40 cm
Explanation:
A microscope is an optical instrument built by two lenses in such a way that the image of the first is formed within the distance of the other (eyepiece), so that the latter creates an enlarged virtual image of the object, for which the magnification of the microscope is the same to the multiplication of the magnification of each lens
M = - L / f₀ (25 cm /)
where fo and fe are the focal lengths of the objective and eyepiece, 25 cm is the near vision distance and L is the length of the microscope
L = - M f_{o} f_{e} / 25
let's calculate
L = - (-100) 2 5/25
L = 40 cm
Answer:
<u>For proton:</u>
A. The proton is released from Vb (highest potential)
B. v = 2.9x10⁴ m/s
<u>For electron:</u>
A. The electron is released from Va (lowest potential)
B. v = 1.2x10⁶ m/s
Explanation:
<u>For a proton we have</u>:
A. To find the origin from which the proton was released we need to remember that in a potential difference, a proton moves from the highest potential to the lowest potential.
Having that:
Va = 1.51 V and Vb = 5.81 V
We can see that the proton moves from Vb to Va, hence the proton was released from Vb.
B. We now that the work done by an electric field is given by:
(1)
Where:
q: is the proton's charge = 1.6x10⁻¹⁹ C
V: is the potential
Also, the work is equal to:
(2)
Where:
K: is the kinetic energy
m: is the proton's mass = 1.67x10⁻²⁷ kg
: is the velocity in the point a
: is the velocity in the point b = 0 (starts from rest)
Matching equation (1) with (2) we have:
<u>For an electron we have</u>:
A. For an electron we know that it moves from the lowest potential (Va) to the highest potential (Vb), so it is released from Va.
B. The speed is:
Since = 0 (starts from rest) and
= 9.1x10⁻³¹ kg (electron's mass), we have:
I hope it helps you!