Try to draw Humpty Dumty cracked on the floor with men all around him
In collision that are categorized as elastic, the total kinetic energy of the system is preserved such that,
KE1 = KE2
The kinetic energy of the system before the collision is solved below.
KE1 = (0.5)(25)(20)² + (0.5)(10g)(15)²
KE1 = 6125 g cm²/s²
This value should also be equal to KE2, which can be calculated using the conditions after the collision.
KE2 = 6125 g cm²/s² = (0.5)(10)(22.1)² + (0.5)(25)(x²)
The value of x from the equation is 17.16 cm/s.
Hence, the answer is 17.16 cm/s.
Answer:
The frictional force producing this deceleration would have a magnitude of
.
Explanation:
The velocity of this object changed by
in
. The acceleration of this object would be:
.
Let
denote the mass of this object. By Newton's Second Law of Motion, the net force on this object would be:
.
(
.)
If the floor is level, friction would be the only unbalanced force on this object. Thus, the magnitude of the frictional force on this object would also be
, same as the magnitude of the net force on this object.
<span>buzzed, droned, jangled, reverberated.</span>