Answer:
M
Explanation:
Concentration of ![Cu^{2+} = [Cu(NO_3)_2]](https://tex.z-dn.net/?f=Cu%5E%7B2%2B%7D%20%3D%20%5BCu%28NO_3%29_2%5D)
= 0.020 M
Constructing an ICE table;we have:
![Cu^{2+}+4NH_3_{aq} \rightleftharpoons [Cu(NH_3)_4]^{2+}_{(aq)}](https://tex.z-dn.net/?f=Cu%5E%7B2%2B%7D%2B4NH_3_%7Baq%7D%20%5Crightleftharpoons%20%5BCu%28NH_3%29_4%5D%5E%7B2%2B%7D_%7B%28aq%29%7D)
Initial (M) 0.020 0.40 0
Change (M) - x - 4 x x
Equilibrium (M) 0.020 -x 0.40 - 4 x x
Given that: 
![K_f } = \frac{[Cu(NH_3)_4]^{2+}}{[Cu^{2+}][NH_3]^4}](https://tex.z-dn.net/?f=K_f%20%7D%20%3D%20%5Cfrac%7B%5BCu%28NH_3%29_4%5D%5E%7B2%2B%7D%7D%7B%5BCu%5E%7B2%2B%7D%5D%5BNH_3%5D%5E4%7D)
Since x is so small; 0.40 -4x = 0.40
Then:
M
Answer:
Try everything
1. How many moles of nitrogen gas are in 1.54x10^26 molecules? How many atoms?
2. How many molecules of water are in 3.45 moles of water?
3. How many atoms of C are in 2.00 moles of Cv6Hv12Ov6? (v means the number is below)
Explanation:
Answer:
Because u would have to find the undercorse of 010-1 witch makes the out of part by 6
Explanation:
Given :
Juan rolled a six-sided number cube 18 times.
The number two occurred four times.
To Find: Juan claimed the experimental probability of rolling a two was approximately 1/9. Why is Juan’s experimental probability incorrect?
Solution:
Total events = number of times cube rolled = 18
Favorable events = The number two occurred four times. = 4
So, Experimental probability of rolling a two was approximately 1/9
