What do simple machines increase? Force Density Work Mechanical advantage

1 answer:

4 0

The wheel and axle increases your force. You exert your input force over a long distance and the output force is increased over a shorter distance. (Because the wheel is larger than the axle, the axle rotates and exerts a large output force.) A simple machine with a grooved wheel with a rope or cable wrapped around it.

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In a chemical reaction, the total charge of the reactants must be

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the same with that of products

Explanation:

In a chemical reaction, the total charge of the reactants must be the same with that of products.

Charges must be conserved or balanced in chemical reactions.

In both acidic and basic/neutral medium electrons are used to balance the charge.
The appropriate number of electrons is added to the side with a larger charge.
One electron is used to balance each positive charge.
This ensures that the sum of charges on both sides the same.

Learn more:

Balanced equation brainly.com/question/5297242

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There are stars located in the center bulge of the Milky Way and the spiral arms of the Milky Way. What is the difference betwee

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The stars at the center bulge are bigger and brighter than the stars in the arms.

Explanation:

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3 years ago

From the top of a tall building, a gun is fired. The bullet leaves the gun at a speed of 340 m/s, parallel to the ground. As the

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Answer:

The launching point is at a distance D = 962.2m and H = 39.2m

Explanation:

It would have been easier with the drawing. This problem is a projectile launching exercise, as they give us data after the window passes and the wall collides, let's calculate with this data the speeds at the point of contact with the window.

X axis

x = Vox t

t = x / vox

t = 7.1 / 340

t = 2.09 10-2 s

In this same time the height of the window fell

Y = Voy t - ½ g t²

Let's calculate the initial vertical speed, this speed is in the window

Voy = (Y + ½ g t²) / t

Voy = [0.6 + ½ 9.8 (2.09 10⁻²)²] /2.09 10⁻² = 0.579 / 0.0209

Voy = 27.7 m / s

We already have the speed at the point of contact with the window. Now let's calculate the distance (D) and height (H) to the launch point, for this we calculate the time it takes to get from the launch point to the window; at this point the vertical speed is Vy2 = 27.7 m / s

Vy = Voy - gt₂

Vy = 0 -g t₂

t₂ = Vy / g

t₂ = 27.7 / 9.8

t₂ = 2.83 s

This is the time it also takes to travel the horizontal and vertical distance

X = Vox t₂

D = 340 2.83

D = 962.2 m

Y = Voy₂– ½ g t₂²

Y = 0 - ½ g t2

H = Y = - ½ 9.8 2.83 2