Question

A technician wraps wire around a tube of length 38 cm having a diameter of 8.3 cm. When the windings are evenly spread over the full length of the tube, the result is a solenoid containing 555 turns of wire.(a) Find the inductance of this solenoid.

Answer 1

Answer:

The inductance of this solenoid is 5.51 mH.

Explanation:

Given that,

length of the tube, l = 38 cm = 0.38 m

Diameter of the tube, d = 8.3 cm

Radius of the tube, r = 4.15 cm

The number of turns, N = 555

We need to find the inductance of this solenoid. It is given by the formula as :

$L=\dfrac{\mu N^2A}{l}\\\\L=\dfrac{4\pi \times 10^{-7}\times 555^2\times \pi \times (4.15\times 10^{-2})^2}{0.38}\\\\L=0.00551\ H\\\\L=5.51\ mH$

So, the inductance of this solenoid is 5.51 mH. Hence, this is the required solution.