Answer:
Explanation:
Time for one dot = 1 /50 = .02 s
Distance between 3 rd and fourth dot is 3 cm and time taken to travel this distance is .02 s
velocity = 3 cm / .02 = 150 cm /s
Distance between 4 th and 5 th dot is 4 cm and time taken to travel this distance is .02 s
velocity = 4 cm / .02 = 200 cm /s
change in velocity = 200 cm/s - 150cm/s = 50 cm /s
Time taken = .02 s
Acceleration = 50 / .02 cm/s²
= 2500 cm/s²
The box is in equilibrium, so Newton's second law says
<em>n</em> + (-<em>w</em>) = 0
65 N + (-<em>f</em> ) = 0
where <em>n</em> denotes the magnitude of the normal force, <em>w</em> denotes the weight of the box, and <em>f</em> denotes the magnitude of the friction force.
The box has a weight of
<em>w</em> = (25 kg) (9.80 m/s²) = 245 N
so <em>n</em> = 245 N, too.
The friction force has magnitude
<em>f</em> = 65 N
and is proportional to the normal force by a factor of <em>µ</em>, the coefficient of kinetic friction. So we have
65 N = <em>µ</em> (245 N) → <em>µ</em> ≈ 0.26
W=F*s
W=9000*0
W=0
W:Work
F:Force
s:Distance
Answer:
The horizontal distance traveled by the projectile is 15.23 m.
Explanation:
Given;
angle of projection, θ = 25⁰
initial velocity of the projectile, u = 15 m/s
time of flight, t = 1.12 s
The the travelling path of the object is calculated as the range of the projectile
Therefore, the horizontal distance traveled by the projectile is 15.23 m.
Cardiac, smooth, and skeletal. cardiac muscle cells are located in the walls of the heart and appear striated and are under involuntary control. smooth muscle fibers are located in walls of hollow visceral organs except the heart they also appear striated. skeleton muscle is found between bones and uses tendons to connect to the epimysium to the periosteum, or the outer covering of bone. skeletal muscle is shaped and adapted in many ways.
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