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3 years ago

Chemical reactions chemical equilibrium occurs when the rates of the reactions

Chemistry

1 answer:

TiliK225 [7]3 years ago

4 0

I believe it would be A. Equal out in both directions.

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did this and got 8.3 x 10-5 can someone help me figure out how i got this wrong since these are the only answer choices?

Bezzdna [24]

It is b i think bc it looks like it would be it and my tudor helped me

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3 years ago

How does a heat affect the chemical reaction?

patriot [66]

Answer:

Increasing the temperature increases reaction rates because of the disproportionately large increase in the number of high energy collisions. It is only these collisions (possessing at least the activation energy for the reaction) which result in a reaction.

Explanation:

6 0

3 years ago

Read 2 more answers

The most simple level of organization in living things is the tissue level.

murzikaleks [220]

The simplest level of organization for living things is a single organelle, which is composed of aggregates of macromolecules. so it is false

3 0

3 years ago

Read 2 more answers

PLS HELP: CHEMISTRY

user100 [1]

Answer:

3.59x10^21 molecules

Explanation:

1mole of a substance contains 6.02x10^23 molecules.

Therefore, 1mole of C8H18 will also contain 6.02x10^23 molecules

1mole of C8H18 = (12x8) +(18x1) = 96 + 18 = 114g.

1mole (i.e 114g) oh C8H18 contains 6.02x10^23 molecules.

Therefore, 0.68g of C8H18 will contain = (0.68 x 6.02x10^23)/114 = 3.59x10^21 molecules

7 0

3 years ago

A student placed 10.5 g of glucose (C6H12O6) in a volumetric fla. heggsk, added enough water to dissolve the glucose by swirling

aniked [119]

Answer: The mass of glucose in final solution is 0.420 grams

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$ .........(1)

Initial mass of glucose = 10.5 g

Molar mass of glucose = 180.16 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$\text{Initial molarity of glucose}=\frac{10.5\times 1000}{180.16\times 100}\\\\\text{Initial molarity of glucose}=0.583M$

To calculate the molarity of the diluted solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated glucose solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted glucose solution

We are given:

$M_1=0.583M\\V_1=20.0mL\\M_2=?M\\V_2=0.5L=500mL$

Putting values in above equation, we get:

$0.583\times 20=M_2\times 500\\\\M_2=\frac{0.583\times 20}{500}=0.0233M$

Now, calculating the mass of final glucose solution by using equation 1:

Final molarity of glucose solution = 0.0233 M

Molar mass of glucose = 180.16 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$0.0233=\frac{\text{Mass of glucose in final solution}\times 1000}{180.16\times 100}\\\\\text{Mass of glucose in final solution}=\frac{0.0233\times 180.16\times 100}{1000}=0.420g$

Hence, the mass of glucose in final solution is 0.420 grams

3 0

4 years ago