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Butoxors [25]
3 years ago
7

Waves combine to make wave with a smaller amplitude in a process called?

Chemistry
2 answers:
Anettt [7]3 years ago
5 0
Waves combine to make a wave with a smaller amplitude in a process called constructive interference.

~Happy Studying! ^^


inysia [295]3 years ago
3 0
The answer would be : constructive interference.

Hope this helps !

Photon
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How can phisical change what a subtance?
solmaris [256]
Physical change can change a substance by affecting the form of a chemical change.
Examples of physical changes:
Something cut (Paper)
Molded (Bread)
Boiled (Water)
Mixed (Berries and strawberries)
HOPE THIS HELPS YOU! ^_^

3 0
4 years ago
ANSWERIT AND YOU WILL BE MARKED THE BRAINLIEST
fgiga [73]

Answer:

The answer is definitely D

Explanation:

3 0
3 years ago
Read 2 more answers
Please help This is for my chemistry class and I need to get it done but I’m lost and need answers
Vanyuwa [196]

Answer:

chlorine is a non metal.

sodium is a alkali metal.

helium is a noble gas.

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5 0
2 years ago
Which formula is an empirical formula?
poizon [28]
<h2>Hello!</h2>

The answer is:

The empirical formula is the option B. NH_{3}

<h2>Why?</h2>

The empirical formula of a compound is the simplest formula that can be written. On the opposite, the molecular formula involves a variant of the same compound, but it can be also simplified to an empirical formula.

MolecularFormula=n(EmpiricalFormula)

We are looking for a formula that cannot be simplified by dividing the number of molecules/atoms that conforms the compound.

Let's discard option by option in order to find which formula is an empirical formula (cannot be simplified)

A. N_{2}O_{4}

It's not an empirical formula, it's a molecular formula since it can be obtained by multiplying the empirical formula of the same compound.

N_{2}O_{4}=2(NO_{2})

B. NH_{3}

It's an empirical formula since it cannot be obtained by the multiplication of a whole number and the simplest formula. It's the simplest formula that we can find of the compound.

C. C_{3}H_{6}

It's not an empirical formula, it's a molecular formula since it can be obtained by multiplying the empirical formula of the same compound.

C_{3}H_{6}=3(CH_{2})

D. P_{4}O_{10}

It's not an empirical formula, it's a molecular formula since it can be obtained by multiplying the empirical formula of the same compound.

P_{4}O_{10}=2(P_{2}O_{5})

Hence, the empirical formula is the option B. NH_{3}

Have a nice day!

6 0
4 years ago
Read 2 more answers
Determine the basic oxidation<br>number for elements in s and p<br>orbitals​
Andrews [41]

Answer:

Explanation:

The oxidation state, sometimes referred to as oxidation number, describes the degree of oxidation (loss of electrons) of an atom in a chemical compound. Conceptually, the oxidation state, which may be positive, negative or zero, is the hypothetical charge that an atom would have if all bonds to atoms of different elements were 100% ionic, with no covalent component. This is never exactly true for real bonds.

The term oxidation was first used by Antoine Lavoisier to signify reaction of a substance with oxygen. Much later, it was realized that the substance, upon being oxidized, loses electrons, and the meaning was extended to include other reactions in which electrons are lost, regardless of whether oxygen was involved.

Helped?

Brainliest?

7 0
3 years ago
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