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ruslelena [56]
3 years ago
13

Known as the twilight zone, the mesopelagic zone meets the photic zone above and becomes very dark as depth increases. Temperatu

re decrease; pressure increases. Because nutrients are limited here, some animals rise to the photic zone at night for food. Many animals in this subzone can eat animals larger than themselves because they are equipped with large sharp teeth with expandable jaws and stomachs. Another key physical feature of animals living in this zone is ____________, which has a variety of purposes, including predator deterrence, communication, and lures for prey.
A) symbiosis
B) transparency
C) bioluminescence
D) oversized scales
Physics
2 answers:
podryga [215]3 years ago
8 0

Answer: C) bioluminescence

The middle layer of the world's ocean receives very little sunlight. This oceanic layer is called as twilight zone or diphotic zone or mesopelagic zone. This zone appears blue to black in color. The animals that live in this zone are adapted to survive in darkness, high pressure and cold water conditions.

The animals in this zone exhibit large eyes, which helps them to see in dark waters. Most animals are small, thin and dark which helps them to camouflage the predators in darkness. Some animals also possess large teeth and jaws. Many of these animals show bio luminescence, which means they can produce their own light. They have special organs which helps them to produce light by chemical reactions. Animals use light to find food and mates, they camouflage and distract the predators by light.

solmaris [256]3 years ago
6 0

Answer:

C. Bio-luminescence

Explanation:

Twilight zones is also called meso-pelagic of diphotic zone. this is the zone in the ocean which receives very less sunlight so it appears blue or black in color.The animal which lives in this zone have adapted the capability to live under high pressure, in darkness and in low temperature so they have big eyes to watch the things in dark. Generally they are dark in color to camouflage the predators.

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The radius of a dime is approximately r_{n2} = 9\cdot 10^{-3}m: if we assume that the radius of the nucleus is exactly this value, then we  can find how far is the electron by using the proportion
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r_{e2}= \frac{r_{e1} r_{n2}}{r_{n1}}= \frac{(5.3 \cdot 10^{-11}m)(9\cdot 10^{-3}m)}{1 \cdot 10^{-15}m}=477 m

So, if the nucleus had the size of a dime, we would find the electron approximately 500 meters away.
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