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Liula [17]
3 years ago
8

The cylinder C is being lifted using the cable and pulley system shown.

Engineering
1 answer:
Sonja [21]3 years ago
4 0

Answer:

sry but it's kinda hard

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Type the correct answer in the box. Spell all words correctly.
Otrada [13]

Answer:

solar engineering field

5 0
3 years ago
Read 2 more answers
6) A deep underground cavern Contains 980 cuft
Elza [17]

Answer:

15625 moles of methane is present in this gas  deposit

Explanation:

As we know,

PV = nRT

P = Pressure = 230 psia = 1585.79 kPA

V = Volume = 980 cuft = 27750.5 Liters

n = number of moles

R = ideal gas constant = 8.315

T = Temperature = 150°F = 338.706 Kelvin

Substituting the given values, we get -

1585.79 kPA * 27750.5 Liters = n * 8.315 * 338.706 Kelvin

n = (1585.79*27750.5)/(8.315 * 338.706) = 15625

3 0
2 years ago
A. Calculate the concentration of a toxic (Cout) that is added to a lake with an input concentration of 100 μg/l. The flow rate
Mazyrski [523]

Answer:

Calt =42.129 mg/eit

Explanation:

See attached image

5 0
3 years ago
Some Tiny College staff employees i s are information technology (IT) personnel. Some IT personnel provide technology support fo
Westkost [7]

Answer:

solution in the picture attached

Explanation:

3 0
3 years ago
(SI units) Molten metal is poured into the pouring cup of a sand mold at a steady rate of 400 cm3/s. The molten metal overflows
maxonik [38]

Answer:

diameter of the sprue at the bottom is 1.603 cm

Explanation:

Given data;

Flow rate, Q = 400 cm³/s

cross section of sprue: Round

Diameter of sprue at the top d_{top} = 3.4 cm

Height of sprue, h = 20 cm = 0.2 m

acceleration due to gravity g = 9.81 m/s²

Calculate the velocity at the sprue base

V_{base} = √2gh

we substitute

V_{base} = √(2 × 9.81 m/s² × 0.2 m )

V_{base} = 1.98091 m/s

V_{base} = 198.091 cm/s

diameter of the sprue at the bottom will be;

Q = AV = (πd_{bottom}^2/4) × V_{base}

d_{bottom} = √(4Q/πV_{base})

we substitute our values into the equation;

d_{bottom} = √(4(400 cm³/s) / (π×198.091 cm/s))

d_{bottom}  = 1.603 cm

Therefore, diameter of the sprue at the bottom is 1.603 cm

6 0
2 years ago
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