Answer:
7ft (2.13 m).
Explanation:
From the question above, the following parameters/data are given; the room dimension = 12 ft × 18 ft (∼3.7 m × ∼5.5 m), the floor-to-ceiling height = 9 ft (2.8 m) and the spacing ratio for the luminaire is 1:0.
Note that, we are not given the value or data for the height of the plane, therefore, we will make an assumption that the height of the plane = 2ft.
Hence, the work plane to luminaire distance = (9 - 2)ft = 7ft (2.13 m).
So, the maximum distance that the luminaires can be separated and achieve uniform illuminance is;
= the work plane to luminaire distance × spacing ratio for the luminaire.
= 7ft (2.13 m) × 1 = 7ft (2.13 m).
Thus, the maximum distance that the luminaires can be separated and achieve uniform illuminance is 7ft (2.13 m).
We know that

So, the volume of the entire building is

The flow capacity of the fan


As 

For the other part we know

The diameter is,


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Answer:
the overall heat transfer coefficient of this heat exchanger is 1855.8923 W/m²°C
Explanation:
Given:
d₁ = diameter of the tube = 1 cm = 0.01 m
d₂ = diameter of the shell = 2.5 cm = 0.025 m
Refrigerant-134a
20°C is the temperature of water
h₁ = convection heat transfer coefficient = 4100 W/m² K
Water flows at a rate of 0.3 kg/s
Question: Determine the overall heat transfer coefficient of this heat exchanger, Q = ?
First at all, you need to get the properties of water at 20°C in tables:
k = 0.598 W/m°C
v = 1.004x10⁻⁶m²/s
Pr = 7.01
ρ = 998 kg/m³
Now, you need to calculate the velocity of the water that flows through the shell:

It is necessary to get the Reynold's number:

Like the Reynold's number is greater than 10000, the regime is turbulent. Now, the Nusselt's number:

The overall heat transfer coefficient:

Here

Substituting values:

Answer:
True
Explanation:
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Hope this will help!