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Liula [17]
3 years ago
8

The cylinder C is being lifted using the cable and pulley system shown.

Engineering
1 answer:
Sonja [21]3 years ago
4 0

Answer:

sry but it's kinda hard

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g a heat engine is located between thermal reservoirs at 400k and 1600k. the heat engine operates with an efficiency that is 70%
Bond [772]

Answer:

<em>Heat rejected to cold body = 3.81 kJ</em>

Explanation:

Temperature of hot thermal reservoir Th = 1600 K

Temperature of cold thermal reservoir Tc = 400 K

<em>efficiency of the Carnot's engine = 1 - </em>\frac{Tc}{Th}<em> </em>

eff. of the Carnot's engine = 1 - \frac{400}{600}

eff = 1 - 0.25 = 0.75

<em>efficiency of the heat engine = 70% of 0.75 = 0.525</em>

work done by heat engine = 2 kJ

<em>eff. of heat engine is gotten as = W/Q</em>

where W = work done by heat engine

Q = heat rejected by heat engine to lower temperature reservoir

from the equation, we can derive that

heat rejected Q = W/eff = 2/0.525 = <em>3.81 kJ</em>

6 0
3 years ago
The barrel of a bicycle tire pump becomes quite warm during use. Explain the mechanisms responsible for the temperature increase
Alexeev081 [22]

Answer:

The air heats up when being compressed and transefers heat to the barrel.

Explanation:

When a gas is compressed it raises in temperature. Assuming that the compression happens fast and is done before a significant amount of heat can be transferred to the barrel, we could say it is an adiabatic compression. This isn't exactly true, it is an approximation.

In an adiabatic transformation:

P^{1-k} * T^k = constant

For air k = 1.4

SO

P0^{-0.4} * T0^{1.4} = P1^{-0.4} * T1^{1.4}

T1^{1.4} = \frac{P1^{0.4} * T0^{1.4}}{P0^{0.4}}

T1^{1.4} = \frac{P1}{P0}^{0.4} * T0^{1.4}

T1 = T0 * \frac{P1}{P0}^{0.4/1.4}

T1 = T0 * \frac{P1}{P0}^{0.28}

SInce it is compressing, the fraction P1/P0 will always be greater than one, and raised to a positive fraction it will always yield a number greater than one, so the final temperature will be greater than the initial temperature.

After it was compressed the hot air will exchange heat with the barrel heating it up.

5 0
3 years ago
1. Two aluminium strips and a steel strip are to be bonded together to form a composite bar. The modulus of elasticity of steel
yarga [219]

Answer:

1.933 KN-M

Explanation:

<u>Determine the largest permissible bending moment when the composite bar is bent  horizontally </u>

Given data :

modulus of elasticity of steel = 200 GPa

modulus of elasticity of aluminum = 75 GPa

Allowable stress for steel = 220 MPa

Allowable stress for Aluminum = 100 MPa

a = 10 mm

<em>First step </em>

determine moment of resistance when steel reaches its max permissible stress

<em>next </em>: determine moment of resistance when Aluminum reaches its max permissible stress

Finally Largest permissible bending moment of the composite Bar = 1.933 KN-M

<em>attached below is a detailed solution </em>

5 0
3 years ago
What is the main reason for using a complex data table?
wolverine [178]

Answer:

D. To interpret the possible meaning of the data

7 0
3 years ago
Read 2 more answers
If a mineral fractures, how many directions of cleavage does it have?
Sveta_85 [38]

Answer:

Cleavage occurs in straight lines in a mineral, with different minerals exhibiting 1, 2, or 3 directions of cleavage. Fractures however are irregular and follow how specific pattern or cleavages

3 0
3 years ago
Read 2 more answers
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