Answer:
93.57 KJ/s
Explanation:
Rate of heat transfer from the steam to the cooling water = mass rate × Heat of vaporization of water at 40 °C
H vaporization of water 40 °C at saturation pressure = 2406.0 kJ / Kg
rate of heat transfer = 2406.0 kJ / Kg × 140 Kg / ( 60 × 60s) = 93.57 KJ/s
This an example solved please follow up with they photo I sent ok
Answer:
They communicate ideas very quickly.
Explanation:
