Answer:
Your question lacks the time required hence i will calculate the Average flow rate using a general concept and an assumed time value of 25 seconds
ANSWER : 104.904 ft^3/sec
Explanation:
General concept : Average flow rate is the volume of fluid per unit time through an area
Hence the average flow rate of the air conditioning unit of this room
Volume of the room / time taken for the air to cycle the room = v / t
assuming the time taken = 25 seconds
volume of room = width * length * height
= 14.1 * 15.5 * 12 = 2622.6 ft^3
Average flow rate = V/ t
= 2622.6 / 25 = 104.904 ft^3/sec
Answer:
than look inside it
Explanation:
well if you need to inspect something, looking is very important
Answer:
C. exactly vertical
Explanation:
"Plumb" means "exactly vertical."
Answer:
1709.07 ft^3/s
Explanation:
Annual peak streamflow = Log10(Q [ft^3/s] )
mean = 1.835
standard deviation = 0.65
Probability of levee been overtopped in the next 15 years = 1/5
<u>Determine the design flow ins ft^3/s </u>
P₁₅ = 1 - ( q )^15 = 1 - ( 1 - 1/T )^15 = 0.2
∴ T = 67.72 years
Q₁₅ = 1 - 0.2 = 0.8
Applying Lognormal distribution : Zt = mean + ( K₂ * std ) --- ( 1 )
K₂ = 2.054 + ( 67.72 - 50 ) / ( 100 - 50 ) * ( 2.326 - 2.054 )
= 2.1504
back to equation 1
Zt = 1.835 + ( 2.1504 * 0.65 ) = 3.23276
hence:
Log₁₀ ( Qt(ft^3/s) ) = Zt = 3.23276
hence ; Qt = 10^3.23276
= 1709.07 ft^3/s
