Answer:
I = 4.642 Ampere.
x = 2.145 cm
Explanation:
a) As we know, the magnetic field on the axis of the loop is given as
![B = \frac{ \mu NIa^{2} }{2(x^{2} + a^{2})^{\frac{3}{2} } }](https://tex.z-dn.net/?f=B%20%3D%20%5Cfrac%7B%09%5Cmu%20NIa%5E%7B2%7D%20%7D%7B2%28x%5E%7B2%7D%20%2B%20a%5E%7B2%7D%29%5E%7B%5Cfrac%7B3%7D%7B2%7D%20%7D%20%20%20%7D)
where a = radius of loop
x = point on the axis of loop
N = No of turns of coil
Current in the loop for which the magnetic field at the center is 0.0750 Tesla is given as x = 0
Therefore, the above equation can be rewritten as
![B_{x} = \frac{ \mu NI}{2a}](https://tex.z-dn.net/?f=B_%7Bx%7D%20%20%3D%20%5Cfrac%7B%09%5Cmu%20NI%7D%7B2a%7D)
I = ![\frac{2aB}{μN}](https://tex.z-dn.net/?f=%5Cfrac%7B2aB%7D%7B%CE%BCN%7D)
by putting values
I =![\frac{2 X 0.0750 T X 0.028 m}{4\pi X 10^{-7} T.\frac{m}{A} X 720}](https://tex.z-dn.net/?f=%5Cfrac%7B2%20X%200.0750%20T%20X%200.028%20m%7D%7B4%5Cpi%20X%2010%5E%7B-7%7D%20T.%5Cfrac%7Bm%7D%7BA%7D%20%20X%20720%7D)
Current in the loop for which the magnetic field at the center is 0.0750 Tesla = I = 4.642 Ampere
b)
Now for part b the magnetic field at a distance x from the center is given as
![B = \frac{ \mu N I a^{2} }{2(x^{2} + a^{2})^{\frac{3}{2} } }](https://tex.z-dn.net/?f=B%20%3D%20%5Cfrac%7B%09%5Cmu%20N%20I%20a%5E%7B2%7D%20%7D%7B2%28x%5E%7B2%7D%20%2B%20a%5E%7B2%7D%29%5E%7B%5Cfrac%7B3%7D%7B2%7D%20%7D%20%20%7D)
multiply and divide by a on both sides we get
![B = \frac{ \mu NI}{2a} X \frac{a^{3} }{(x^{2} + a^{2})^{\frac{3}{2} } }](https://tex.z-dn.net/?f=B%20%3D%20%5Cfrac%7B%09%5Cmu%20NI%7D%7B2a%7D%20X%20%5Cfrac%7Ba%5E%7B3%7D%20%7D%7B%28x%5E%7B2%7D%20%2B%20a%5E%7B2%7D%29%5E%7B%5Cfrac%7B3%7D%7B2%7D%20%7D%20%20%20%7D)
As we know, according to Biot sivorts law,the Magnetic Field at the Center of a circular loop is given as
( Magnetic field at center) = ![B_{c}](https://tex.z-dn.net/?f=B_%7Bc%7D)
So we got magnetic field at any point x as
=
X ![\frac{a^{3} }{(x^{2} + a^{2})^{\frac{3}{2} } }](https://tex.z-dn.net/?f=%5Cfrac%7Ba%5E%7B3%7D%20%7D%7B%28x%5E%7B2%7D%20%2B%20a%5E%7B2%7D%29%5E%7B%5Cfrac%7B3%7D%7B2%7D%20%7D%20%20%20%7D)
For magnetic field at x is half of the B at center
=
from the above two equations
= ![\frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D)
![(x^{2} + a^{2})^{3} = 4a^{6}](https://tex.z-dn.net/?f=%28x%5E%7B2%7D%20%2B%20a%5E%7B2%7D%29%5E%7B3%7D%20%3D%204a%5E%7B6%7D)
Putting a = 2.80 cm
We have x = 2.145 cm Ans
μ
Answer:
1. observational
2. clinical trial
*3. meta analysis*
Explanation:
Hopefully this is correct but if its not I apoligize
Answer:
Following are given the answers one-by-one with explanation:
(a) 8 records
As records are the horizontal rows of data and we have 8 of them.
(b) 5 fields
As fields are vertical columns of data and we have 5 of them.
(c)E3000
As by sorting Makers_names in ascending order the last one would be Rany and by sorting Processor_type we have two option with Rany that are B1500 and E3000. We can see that E3000 will come at the end.
(d) Computer_type
As only two choices (Laptop and PC ) are being used under the column computer_type so it can be amended to contain Boolean data.
(e) format check
This will check that the field should contain one alphabet (capital letter) followed by 4 digits each.
i hope it will help you!
Answer:
The question doesnt make any sense. Like what are the lines used for.
Explanation:
Answer:
From the question, we have two variables
1. userNum1
2. userNum2
And we are to print "userNum1 is negative" if userNum1 is less than 0.
Then Assign userNum2 with 2 if userNum2 is greater than 10.
Otherwise, print "userNum2 is less or equal 10.".
// Program is written in C++ Programming Language
// Comments are used for explanatory purpose
// Program starts here
#include<iostream>
using namespace std;
int main ()
{
// Declare variables
int userNum1, userNum2;
// Accept input for these variables
cin>>userNum1, userNum2;
// Condition 1
if(userNum1 < 0)
{
cout<<"userNum1 is negative"<<'\n';
}
// Condition 2
if(userNum2 > 10)
{
userNum2 = 2;
}
// If condition is less than 10
else
{
cout<<"userNum2 is less or equal to 10"<<\n;
}
return 0;
}
// End of Program.