Answer:
<em>The direction of ball will be Number 4 (as can be seen in attached picture) ---- the path of ball will be making some angle when it leaves the tube. </em>
Explanation:
The question is incomplete. So the picture, which is missing in question, is attached for your review.
As it can be seen in the picture, the ball coming out of the tube will have two components of velocity. One is along the length of tube (because ball is moving in that direction and is coming out from the hole), other is velocity component will be perpendicular to the tube (because the ball is made to move in that direction as the tube is rolling on the surface).
<em>So, taking the resultant of two vectors of velocity, the resultant direction of ball will be Number 4 (as can be seen in attached picture) ---- the path of ball will be making some angle when it leaves the tube. </em>
Answer:
0 m/s , 3 m/s , 2 m/s^2
Explanation:
Given : s(t) = ( t^2 - 6t + 5)
v(t) = ds / dt = 2t - 6
s(0) = 5 m
s(6) = (6)^2 - 6*6 + 5 = 5 m
Vavg = ( s(6) - s(0) ) / 2 = 0 m\s
Find the turning point of particle:
ds/dt = 0 = 2t - 6
t = 3 sec
s(3) = 3^2 -6*3 + 5 = - 4
Total distance = 5 - (-4) + (5 - (-4)) = 18 m
Total time = 6s
Average speed = Total distance / Total time = 18 / 6 = 3 m/s
Taking derivative of v(t) to obtain a(t)
a (t) = dv(t) / dt = 2 m/s^2
Answer:
The axis of motion that is parallel to the spindle axis is always the Z-axis.
Explanation:
Z-Axis Which axis is which depends on the orientation of the spindle.
If the spindle is vertical (Figure 2.1), the Z-axis is vertical. Either the quill or the knee of a vertical spindle mill will move when a Z-axis command is executed.
This is the best answer I could give you, maybe you could show us a pic of the question so we see all the possible choices?
Answer:
Head loss in 100 m length equals 1.00 m.
Explanation:
The head loss in an open channel is calculated using manning's equation as follows

For a asphalt rectangular channel we have
Area of flow = 
Wetted Perimeter = 
manning's roughness coefficient = 0.016
Applying values in the above equation we get

Now we know that
