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3 years ago

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The order of components in a typical flame atomic absorption spectrometer is

1 answer:

Zinaida [17]3 years ago

4 0

The order of components in a typical flame atomic absorption spectrometer is hollow cathode lamp--flame--monochromator--detector

<u>Explanation:</u>

The hollow cathode lamp practices a cathode created of the element of interest with a low internal pressure of inert gas.
Remove scattered light of other wavelengths from the flame. AAS flame includes aiming at first the fuel than the oxidant and then lighting the flame with the instrument's auto-ignition system. Applying flame Ddtroy any analyte ions and breakdown complexes.
The process of the monochromator is to divide analytical lines photons moving through the flame
Photomultiplier tube (PMT) as the detector the PMT determines the intensity of photons of the analytical line exiting the monochromator.

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Consider the following reaction: NaHCO3 + HC2H3O2 → NaC2H3O2 + H2O + CO2 How many g of CO2 would be produced from the complete r

Alenkasestr [34]

<h2>1.25 g of $CO_2$ would be produced from the complete reaction of 25 mL of 0.833 mol/L $HC_3H_3O_2$ with excess $NaHCO_3$ </h2>

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in L)}}$

$0.833M=\frac{\text{Moles of} HC_3H_3O_2\times 1000}{25ml}\\\\\text{Moles of} HC_3H_3O_2 =\frac{0.833mol/L\times 25}{1000}=0.0208mol$

$NaHCO_3+HC_2H_3O_2\rightarrow NaC_2H_3O_2+H_2O+CO_2$

According to stoichiometry:

1 mole of $HC_2H_3O_2$ will give = 1 mole of $CO_2$

0.0208 moles of $HC_2H_3O_2$ will give = $\frac{1}{1}\times 0.0208=0.0208 moles$ of $CO_2$

Mass of $HC_2H_3O_2=moles\times {\text {molar mass}}=0.0208\times 60g/mol=1.25g$

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Calculate the mass of CO2 that can be produced if the reaction of 54.0 g of propane and sufficient oxygen has a 64.0% yield.

Oduvanchick [21]

Answer:

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Explanation:

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First <u>we convert 54.0 g of propane (C₃H₈) into moles</u>, using its <em>molar mass</em>:

54.0 g ÷ 44 g/mol = 1.23 mol C₃H₈

Then we <u>convert 1.23 moles of C₃H₈ into moles of CO₂</u>, using the <em>stoichiometric coefficients</em>:

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