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anygoal [31]
3 years ago
12

The order of components in a typical flame atomic absorption spectrometer is

Chemistry
1 answer:
Zinaida [17]3 years ago
4 0

The order of components in a typical flame atomic absorption spectrometer is hollow cathode lamp--flame--monochromator--detector

<u>Explanation:</u>

  • The hollow cathode lamp practices a cathode created of the element of interest with a low internal pressure of inert gas.
  • Remove scattered light of other wavelengths from the flame. AAS flame includes aiming at first the fuel than the oxidant and then lighting the flame with the instrument's auto-ignition system. Applying flame Ddtroy any analyte ions and breakdown complexes.
  • The process  of the monochromator is to divide analytical lines photons moving through the flame
  • Photomultiplier tube (PMT)  as the detector the PMT determines the intensity of photons of the analytical line exiting the monochromator.
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An unknown compound displays singlets at δ 2.1 ppm and 2.56 ppm in the ratio of 3:2. what is the structure of the compound?
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1) As can be seen from any 1H NMR chemical shift ppm tables, hydrogens which have δ values from 2ppm to 2.3ppm are hydrogens from carbon which is bonded to a carbonyl group. From this, we can conclude that our hydrogens belong to the type, but from 2 different alkyl groups because of 2 different signals.

 

2) So, one alkyl group is CH3 and second one can be CH or CH2.

 

3) If we know that ratio between two types of hydrogens is 3:2, it can be concluded that second alkyl group is CH2. 


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4. The type of thermal energy transfer that heats our homes is called
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5 0
2 years ago
A 10.0 mL sample of HNO3 was exactly neutralized by 13.5 mL of 1.0 M KOH. What is the molarity of the HNO3? Use the titrations f
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n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HNO_3

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH.

We are given:

n_1=1\\M_1=?M\\V_1=10.0mL\\n_2=1\\M_2=1.0M\\V_2=13.5mL

Putting values in above equation, we get:

1\times M_1\times 10.0=1\times 1.0\times 13.5\\\\M_1=1.35M

Thus molarity of HNO_3 is 1.35 M

7 0
3 years ago
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