Write the balanced molecular equation for the neutralization reaction between hcl and ba(oh)2 in aqueous solution. include physi
2 answers:
<u>Answer:</u> The balanced molecular equation is written below
<u>Explanation:</u>
A molecular equation is the chemical equation in which the ionic compounds are written as molecules rather than component ions.
Neutralization reaction is defined as the chemical reaction when an acid reacts with a base to produce a salt and water molecule.
The balanced molecular equation for the reaction of hydrochloric acid and barium hydroxide follows:
By Stoichiometry of the reaction:
2 moles of aqueous solution of hydrochloric acid reacts with 1 mole of aqueous solution of barium hydroxide to produce 1 mole of aqueous solution of barium chloride and 2 moles of liquid water.
Hence, the balanced molecular equation is written above.
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The molecular formula : As₄S₆
<h3>Further explanation</h3>Given
Rate of effusion of arsenic(III) sulfide = 0.28 times the rate of effusion of Ar atoms
Required
The molecular formula
Solution
Graham's law: the rate of effusion of a gas is inversely proportional to the square root of its molar masses or
the effusion rates of two gases = the square root of the inverse of their molar masses:
or
Input the value :
1 = Arsenic(III) sulfide
2 = Ar
MM Ar = 40 g/mol
0.28 = √(40/M₁)
M₁=40 : 0.28²
M₁=510 g/mol
The empirical formula of arsenic(III) sulfide = As₂S₃
(Empirical formula)n = molecular formula
( As₂S₃)n = 510 g/mol
(246.02 g/mol)n = 510 g/mol
n = 2
So the molecular formula : As₄S₆
Answer: Molar concentration of the tree sap have to be 0.783 M
Explanation:
To calculate the concentration of solute, we use the equation for osmotic pressure, which is:
where,
= osmotic pressure of the solution = 19.6 atm
i = Van't hoff factor = 1 (for non-electrolytes)
R = Gas constant =
T = temperature of the solution =
Putting values in above equation, we get:
Thus the molar concentration of the tree sap have to be 0.783 M to achieve this pressure on a day when the temperature is 32°C
Answer : The mass of iron needed is 29.5 grams.
Explanation : Given,
Mass of = 12 g
Molar mass of = 32 g/mol
First we have to calculate the moles of .
Now we have to calculate the moles of
The balanced chemical equation is:
From the reaction, we conclude that
As, 3 moles of react with 4 moles of
So, 0.375 mole of react with
mole of
Now we have to calculate the mass of
Molar mass of = 59 g/mole
Therefore, the mass of iron needed is 29.5 grams.