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mel-nik [20]
3 years ago
13

What side of the worm faces up when placed in the tray when dissection?

Physics
1 answer:
Lelechka [254]3 years ago
8 0

<span>The side of the worm that faces up when placed in the tray for dissection is the smoother side.

</span>You can observe the organs of these tiny creatures by dissecting a preserved earthworm<span>. In dissecting a worm, </span><span>lay the worm on your </span>dissecting tray<span> <span>with its dorsal side facing up.</span></span>

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A helicopter is ascending vertically. a passenger accidentally drops her wallet out the sides of the helicopter when it is 160 m
Advocard [28]

Answer:

(E)56.0 m/s

Explanation:

Height =h=-160 m

Because the wallet moving in downward direction

Time=t=7 s

Final speed of wallet=v=0

We have to find the speed of helicopter ascending  at the moment when the passenger let go of the wallet.

v^2-u^2=2gh

Where g=9.8 m/s^2

Substitute the values

0-u^2=2(-160)\times 9.8

u^2=3136

u=\sqrt{3136}=56m/s

Option (E) is true

8 0
4 years ago
Are moons 1-4 waxing are waning ?
solong [7]

Answer:

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Explanation:

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3 0
3 years ago
A night-light uses 3 W.If the voltage is 120 V, what is the current? A.0.025A B.40 A C.360A D.0.25A
Tomtit [17]
The answer to this question is A. 



6 0
3 years ago
At what speed do a bicycle and its rider, with a combined mass of 100 kg, have the same momentum as a 1400 kg car traveling at 2
likoan [24]
100kg x bicycle speed = 1400 X 2

bicycle speed = 2800/ 100
bicycle speed = 28 m/s
3 0
4 years ago
"Giant Swing", the seat is connected to two cables as shown in the figure (Figure 1) , one of which is horizontal. The seat swin
Bingel [31]
The horizontal force is m*v²/Lh, where m is the total mass. The vertical force is the total weight (233 + 840)N. 

<span>Fx = [(233 + 840)/g]*v²/7.5 </span>

<span>v = 32.3*2*π*7.5/60 m/s = 25.37 m/s </span>

<span>The horizontal component of force from the cables is Th + Ti*sin40º and the vertical component of force from the cable is Ta*cos40º </span>

<span>Thh horizontal and vertical forces must balance each other. First the vertical components: </span>

<span>233 + 840 = Ti*cos40º </span>

<span>solve for Ti. (This is the answer to the part b) </span>

<span>Horizontally </span>

<span>[(233 + 840)/g]*v²/7.5 = Th + Ti*sin40º </span>

<span>Solve for Th </span>

<span>Th = [(233 + 840)/g]*v²/7.5 - Ti*sin40º </span>

<span>using v and Ti computed above.</span>
3 0
3 years ago
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