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mel-nik [20]
3 years ago
13

What side of the worm faces up when placed in the tray when dissection?

Physics
1 answer:
Lelechka [254]3 years ago
8 0

<span>The side of the worm that faces up when placed in the tray for dissection is the smoother side.

</span>You can observe the organs of these tiny creatures by dissecting a preserved earthworm<span>. In dissecting a worm, </span><span>lay the worm on your </span>dissecting tray<span> <span>with its dorsal side facing up.</span></span>

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The great limestones caverns were formed by dripping water. If water droplets of 10 ml fall from a height of 5 m at a rate of 10
loris [4]

The average force of the water droplets is the force given by the impact

per second of the droplets on the limestone floor.

  • The average force exerted on the limestone floor is approximately <u>1.6013 × 10⁻² N</u>

Reasons:

The given parameters are;

Volume of a droplet = 10 ml = 1 × 10⁻⁵ m³

Height from which the water falls, <em>h </em>= 5 meters

Rate at which the water falls = 10 per minute

Required:

The average force exerted on the floor by the water droplets.

Solution:

According to Newton's Second Law of motion, we have;

Force = Rate of change of momentum

Momentum = Mass × Velocity

Mass of a droplet of water = Volume × Density

Density of water = 997 kg/m³

Mass of a droplet = 1 × 10⁻⁵ m³ × 997 kg/m³ = 0.00997 kg

The velocity just before the droplet reaches the ground, v = √(2·g·h)

Where;

g = Acceleration due to gravity ≈ 9.81 m/s²

Which gives;

v = √(2 × 9.81 m/s² × 5 m) ≈ 9.905 m/s

The rate of change in momentum per minute = 1

Therefore;

\displaystyle The \ rate \ of \ change \ in \ momentum = Average \ force = \mathbf{\frac{\Delta Momentum }{\Delta Time}}

ΔMomentum = Mass × ΔVelocity

Considering the 10 drops per minute, we have;

ΔMomentum = 10 × 0.0097 kg × 9.905 m/s = 0.960785 kg·m/s

ΔTime = 1 minute = 60 seconds

Therefore;

\displaystyle Average \ force, \, F_{ave}  \frac{0.960785 \, kg\cdot m/s }{60 \, s} \approx =\mathbf{1.6013 \times 10^{-2} \, N}

  • The average force exerted on the limestone floor by the droplets of water is F_{ave} ≈ <u>1.6013 × 10⁻² N</u>

Learn more about Newton's Second Law of motion and force exerted water here:

brainly.com/question/3999427

brainly.com/question/4197598

3 0
2 years ago
Tell the value of the underlined digit 843,208,732,833 eight is underlined
devlian [24]
The value of the underlined 8 is, hundred billion's. Hope this helped!
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3 years ago
Read 2 more answers
You are trying to climb a castle wall so, from the ground, you throw a hook with a rope attached to it at 24.1 m/s at an angle o
Serhud [2]

Answer:

The value is  h  =  13.2 \  m

Explanation:

From the question we are told that

    The speed of the rope with hook is u =  24 .1 \  m/s

     The angle is  \theta = 65.0^o

      The speed at which it hits top of the wall is  v  =  16.3 m/s

Generally from kinematic equation we have that

      v_y^2  =  u_y ^2 + *  2 (-g)* h

Here h is the height of the wall so

      [16.3 sin (65)]^2 =  [24.1 sin (65)] ^2+   2 (-9.8)* h

=>    h  =  13.2 \  m

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Answer:

A

Explanation:

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