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4 years ago

The ampere is a unit of which physical quantity?

Physics

2 answers:

hram777 [196]4 years ago

7 0

Electrical current is measured using the ampere.

Rama09 [41]4 years ago

4 0

For this case we have by definition, that the Ampere, is the unit of electric current intensity.

For its part, the electric current is a measure of the velocity at which the electric charge flows.

The symbol of the current is A. We have that 1 Ampere is equivalent to an electric charge of a coulomb per second.

$1A = \frac {1C} {s}$

Answer:

$1A = \frac {1C} {s}$

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The belt of one ramp moves at a constant speed such that a person who stands still on it leaves the ramp 64 s after getting on.

Bad White [126]

Answer:

0.74 m/s

Explanation:

given,

time taken by the ramp to cover cliff , t = 64 s

acceleration = 0.37 m/s²

distance traveled by the belt

$x = v_{belt}t_{belt}$

Clifford is moving with constant acceleration

$x = v_ot + \dfrac{1}{2}at^2$ ...(1)

initial velocity is equal to zero

$x =\dfrac{1}{2}at^2$ ........(2)

equating equation (1) and (2)

$v_{belt}t_{belt}=\dfrac{1}{2}at^2$

$v_{belt}t_{belt}=\dfrac{1}{2}a(\dfrac{1}{4}\times t_{belt})^2$

$v_{belt}=\dfrac{1}{32}a t_{belt}$

$v_{belt}=\dfrac{1}{32}\times 0.37 \times 64$

$v_{belt}= 0.74\ m/s$

Speed of the belt is equal to 0.74 m/s

3 0

3 years ago

A person jumps out a fourth-story window 14 m above a firefighter safety net. The survivor stretches the net 1.8 m before coming

Monica [59]

Answer:

The deceleration is $a = - 76.27 m/s^2$

Explanation:

From the question we are told that

The height above firefighter safety net is $H = 14 \ m$

The length by which the net is stretched is $s = 1.8 \ m$

From the law of energy conservation

$KE_T + PE_T = KE_B + PE_B$

Where $KE_T$ is the kinetic energy of the person before jumping which equal to zero(because to kinetic energy at maximum height )

and $PE_T$ is the potential energy of the before jumping which is mathematically represented at

$PE_T = mg H$

and $KE_B$ is the kinetic energy of the person just before landing on the safety net which is mathematically represented at

$KE_B = \frac{1}{2} m v^2$

and $PE_B$ is the potential energy of the person as he lands on the safety net which has a value of zero (because it is converted to kinetic energy )

So the above equation becomes

$mgH = \frac{1}{2} m v^2$

=> $v = \sqrt{2 gH }$

substituting values

$v = 16.57 m/s$

Applying the equation o motion

$v_f = v + 2 a s$

Now the final velocity is zero because the person comes to rest

$0 = 16.57 + 2 * a * 1.8$

$a = - \frac{16.57^2 }{2 * 1.8}$

$a = - 76.27 m/s^2$

4 0

3 years ago

When u write on a piece of glass sheet with a piece of chalk , the writing is not clear explain .

svetlana [45]

Becuse your weighting with chalk that has pigment

6 0

4 years ago

A 0.311 kg tennis racket moving 30.3 m/s east makes an elastic collision with a 0.0570 kg ball moving 19.2 m/s west. Find the ve

Troyanec [42]

The velocity of tennis racket after collision is 14.96m/s

<u>Explanation:</u>

Given-

Mass, m = 0.311kg

u1 = 30.3m/s

m2 = 0.057kg

u2 = 19.2m/s

Since m2 is moving in opposite direction, u2 = -19.2m/s

Velocity of m1 after collision = ?

Let the velocity of m1 after collision be v

After collision the momentum is conserved.

Therefore,

m1u1 - m2u2 = m1v1 + m2v2

$v1 = (\frac{m1-m2}{m1+m2})u1 + (\frac{2m2}{m1+m2})u2$

$v1 = (\frac{0.311-0.057}{0.311+0.057})30.3 + (\frac{2 X 0.057}{0.311 + 0.057}) X-19.2\\\\v1 = (\frac{0.254}{0.368} )30.3 + (\frac{0.114}{0.368}) X -19.2\\ \\v1 = 20.91 - 5.95\\\\v1 = 14.96$

Therefore, the velocity of tennis racket after collision is 14.96m/s

7 0

3 years ago

A monatomic gas is adiabatically compressed to 0.250 of its initial volume. Do each of the following quantities change?

Len [333]

Answer:

Given that

V2/V1= 0.25

And we know that in adiabatic process

TV^န-1= constant

T1/T2=( V1 /V2)^ န-1

So = ( 1/0.25)^ 0.66= 2.5

Also PV^န= constant

So P1/P2= (V2/V1)^န

= (1/0.25)^1.66 = 9.98

A. RMS speed is

Vrms= √ 3RT/M

But this is also

Vrms 2/Vrms1= (√T2/T1)

Vrms2=√2.5= 1.6vrms1

Lambda=V/4π√2πr²N

Lambda 2/lambda 1= V2/V1 = 0.25

So the mean free path can be inferred to be 0.25 times the first mean free path

C. Using

Eth= 3/2KT

So Eth2/Eth1= T2/T1

Eth2= 2.5Eth1

Using CV= 3/2R

Cvf= Cvi

So molar specific heat constant does not change

5 0

3 years ago

Read 2 more answers