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Pavlova-9 [17]
3 years ago
14

Which one of the following is a redox reaction?. 2 Na(g) + Cl2(g) 2 NaCl(s) A. K2Cr2O7(aq) + 2 KOH(aq) 2 K2CrO4(aq) + H2O(l) B.

H2O(l) H+(aq) + OH -(aq) C. Na2CO3(s) + 2 HCl(aq) 2 NaCl(aq) + CO2(g) + H2O(l) D. Ba2+(aq) + SO42-(aq) BaSO4(s)
Chemistry
2 answers:
Morgarella [4.7K]3 years ago
6 0
2Na(g) + Cl2(g)  2NaCl(s) is the redox reaction. Na atoms lose electrons and Cl atoms gain electrons, thereby getting oxidized and reduced respectively and fulfilling the requirement of a redox reaction.
Dmitry [639]3 years ago
6 0

Answer: Option (a) is the correct answer.

Explanation:

A redox reaction is defined as a reaction in which there occurs a change in oxidation state of the reacting species.

For example, 2Na(g) + Cl_{2}(g) \rightarrow 2NaCl(s)

Here, oxidation state of sodium is changing from 0 to +1 and oxidation state of chlorine is changing from 0 to -1.

Therefore, this change in oxidation state of the reactants depicts a redox reaction has occurred.

Thus, we can conclude that out of the given options 2Na(g) + Cl_{2}(g) \rightarrow 2NaCl(s) is a redox reaction.

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The base of toothpaste is magnesium hydroxide.


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What is the mass of the oxygen in one mole of calcium phosphate
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16.00 g/mol

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One atom of an element possesses 80 protons, 80 electrons, and 121 neutrons. Given this information, what is the atomic mass of
IRINA_888 [86]

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Explanation:

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3 0
3 years ago
What volume in mt, of 0.5a M1HCI solution is needed to neutralize 77 ml of 1.54 M NaOH solution?
Rainbow [258]

Answer:

237.2 mL.

Explanation:

  • We have the rule: at neutralization, the no. of millimoles of acid is equal to the no. of millimoles of the base.

(XMV) acid = (XMV) base.

where, X is the no. of (H) or (OH) reproducible in acid or base, respectively.

M is the molarity of the acid or base.

V is the volume of the acid or base.

<em>(XMV) HCl = (XMV) NaOH.</em>

<em></em>

For HCl; X = 1, M = 0.5 M, V = ??? mL.

For NaOH, X = 1, M = 1.54 M, V = 77.0 mL.

<em>∴ V of HCl = (XMV) NaOH / (XV) HCl = (</em>1)(1.54 M)(77.0 mL) / (1)(0.5 M) = <em>237.2 mL.</em>

8 0
3 years ago
Calculate the amount of heat water absorbs from a piece of hot metal using the following data: 75.0 g of cold water is placed in
AysviL [449]

Answer:

Amount of heat absorbed by water is 2604.54 J.

Explanation:

Amount of heat absorbed by water = m_{water}\times C_{water}\times \Delta T_{water}

where m represents mass, C represents specific heat and \Delta T represents change in temperature.

Here m_{water}=75.0 g , C_{water}=4.184J/(g.^{0}\textrm{C}) and \Delta T = (final temperature - initial temperature) = (29.5-21.2) ^{0}\textrm{C} = 8.3 ^{0}\textrm{C}

So, amount of heat heat absorbed by water

     = (75.0g)\times (4.184\frac{J}{g.^{0}\textrm{C}})\times (8.3^{0}\textrm{C})

     = 2604.54 J

8 0
4 years ago
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