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2 years ago

3.

Chemistry

1 answer:

Dovator [93]2 years ago

6 0

Answer : The number of grams of calcium perchlorate is, 0.00253 grams.

Explanation :

Molar mass of calcium perchlorate = 238.9 g/mol

As, $6.022\times 10^{23}$ formula units present in 238.9 g of calcium perchlorate

So, $6.37\times 10^{18}$ formula units present in $\frac{6.37\times 10^{18}}{6.022\times 10^{23}}\times 238.9=0.00253g$ of calcium perchlorate

Therefore, the number of grams of calcium perchlorate is, 0.00253 grams.

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Read 2 more answers

What is the molarity of the potassium hydroxide if 25.25 mL of KOH is required to neutralize 0.500 g of oxalic acid, H2C2O4? H2C

Greeley [361]

Answer:

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First step is to find the number of moles of oxalic acid.

n(oxalic acid) = $\frac{0.5g}{90.03 g/mol} = 5.5537*10^{-3} mol\\$

Now use the molar ratio to find how many moles of NaOH would be required to neutralize $5.5537*10^{-3} mol\\$ of oxalic acid.

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1 : 2 (we get this from the balanced equation)

$5.5537*10^{-3} mol\\$ : x

x = 0.0111 mol

Now to calculate what concentration of KOH that would be in 25 mL of water:

$c = \frac{number of moles}{volume} = \frac{0.0111}{0.025} = 0.444 mol/L$

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