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Gnoma [55]
4 years ago
8

The wind is blowing in the direction of a vector pointing at an angle 30 degrees to the east of due north, at 35 miles/hour. An

airplane that can go 320 miles/hour in still air points itself due north at the start of a race. The other airplane points itself with the wind directly at its back. It can go 305 miles/hour. How long will it take each plane to cover 1 degree of latitude?

Physics
1 answer:
a_sh-v [17]4 years ago
6 0

Answer:

Time for the first plane to cover 1 degree of latitude is 0.2hour

Time for the second plane to cover 1 degree of latitude is 0.203hour

Explanation:

Check attachment for solution

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A 0.500 H inductor is connected in series with a 93 Ω resistor and an ac source. The voltage across the inductor is V = −(11.0V)
bezimeni [28]

Answer:

205 V

V_{R} = 2.05 V

Explanation:

L = Inductance in Henries, (H)  = 0.500 H

resistor is of 93 Ω so R = 93 Ω

The voltage across the inductor is

V_{L} = - IwLsin(wt)

w = 500 rad/s

IwL = 11.0 V

Current:

I = 11.0 V / wL

 = 11.0 V / 500 rad/s (0.500 H)

 = 11.0 / 250

I = 0.044 A

Now

V_{R} = IR

    = (0.044 A) (93 Ω)

V_{R} = 4.092 V

Deriving formula for voltage across the resistor

The derivative of sin is cos

V_{R} = V_{R} cos (wt)

Putting V_{R} = 4.092 V and w = 500 rad/s

V_{R} = V_{R} cos (wt)

    = (4.092 V) (cos(500 rad/s )t)

So the voltage across the resistor at 2.09 x 10-3 s is which means

t = 2.09 x 10⁻³

V_{R} = (4.092 V) (cos (500 rads/s)(2.09 x 10⁻³s))

    =  (4.092 V) (cos (500 rads/s)(0.00209))

    = (4.092 V) (cos(1.045))

    = (4.092 V)(0.501902)

    = 2.053783

V_{R} = 2.05 V

8 0
3 years ago
What three sprites are needed to create the Space Invaders game that was discussed in the unit? spaceship, laser, enemy gnome, a
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Answer: anlien, enemy gnome, spaceship

Explanation:

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What is dark energy?
olga2289 [7]

Explanation:

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The average weather of a particular place is
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3 years ago
Read 2 more answers
A 2.0-cm-diameter, 15-cm-long solenoid is tightly wound with one layer of wire. A 2.5 A current through the wire generates a 3.0
sweet [91]

Answer:

d = 1.047 mm

Explanation:

given,

diameter of the wire = 2.0-cm

length of solenoid = 15 cm = 0.15

Current in the wire = I = 2.5 A

magnetic field = B = 3.0 mT

Magnetic field inside the solenoid

        B = \dfrac{\mu_0 N I}{L}

        B = \dfrac{\mu_0 N I}{L}

               N x d = l

        N = \dfrac{l}{d}

        B = \dfrac{\mu_0 \dfrac{l}{d} I}{L}

        3 \times 10^{-3} = \dfrac{4\pi \times 10^{-7}\times \dfrac{0.15}{d}\times 2.5}{0.15}

        0.45 \times 10^{-3}\ d = 4\pi \times 10^{-7}\times 0.15\times 2.5

        \ d = \dfrac{4\pi \times 10^{-7}\times 0.15\times 2.5}{0.45 \times 10^{-3}}

               d = 1.047 x 10⁻³ m

               d = 1.047 mm

diameter of the wire is d = 1.047 mm

5 0
3 years ago
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