It seems like I begin to forget whole organic Chemistry. Anyway, the answer is 2-methylheptane-3-yne. To build a name for this molecule, you need to: 1. Determine where there is the lowest chain beginning with the double, triple bond, or there is other thing for other types of organic molecules.. In this case you have one triplet bond, and the lowest chain there is the one that is below the bond. 2. In this small chain you see one "forks": CH3 and another CH3 go from the one CH. Put number 1 where there are the most number of such compounds, in this case it doesn't matter because we have one CH3 in one way and one CH3 in the another. 3. Determine the largest chain which surely has the triple bond. Put the numbers from 2 to the final beginning with CH3 where you put number 1. Your largest chain consists of 7 particles CH3, CH2, and CH. 4. You see that you also have one unnamed particle, the one which is "the other way" when you are in the CH which is below the triple bond on the picture. Its name will be 2-methyl because it is connected with particle #2 and it consists only of one carbon. If there were 2, it would be ethyl, and so on. 5. Finally, let's write a full name: put 2-methyl first, "2-methyl." Then, write a full name for the chain of 7 carbons, which has to be heptane, if it had 5, you would name it pentane, ethane, and so on. So, we have "2-methylheptane." Finally, you see that you have a triple bond after the carbon #3. Put a dash and the number of this carbon. "2-methylheptane-3" you should have. Since it is alkyne (organic molecule with one triple bond), you have to write "yne" at the end. the final name is "2-methylheptane-3-yne." You can answer the question "explain your naming process" by using the answer I provided. Hope it helps. Good luck!
1S^2 2S^2 2P^6 3S^2 3P^6 4S^2 3d^10 4P^6 5S^2 4d^10 5P^5 when Krypton is the noble gas in the row above iodine in the periodic table, we can change 1S^2 2S^2 2P^6 3S^2 3P^6 4S^2 3d^10 4P^6 by the symbol [Kr] of Krypton.
So we can write the electron configuration of Iodine: [Kr] 5S^2 4d^10 5P^5
Since liquid isopropanol is a polar liquid and water is also a polar solvent. So, when both of them are added together then according to the like dissolves like principle they get dissolved.
At the molecular level, the polar molecules of isopropanol get attracted towards the polar molecules of water at the surface of water.
As a result, water molecules get surrounded by isopropanol. Thus, water molecules enter the solution and evenly spread into the solution.
The correct answer is Option A. Explanation: Tomato is a citrus fruit which contains citric acid as a main chemical component. This range lies in the range of acidic substances.
