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Pachacha [2.7K]
3 years ago
9

Denise is conducting a physics experiment to measure the acceleration of a falling object when it slows down and comes to a stop

. She drops a wooden block with a mass of 0.5 kilograms on a sensor on the floor. The sensor measures the force of the impact as 4.9 newtons. What’s the acceleration of the wooden block when it hits the sensor? Use F = ma.
A. 2.45 m/s2
B. 4.4 m/s2
C. 5.4 m/s2
D. 9.8 m/s2
Physics
2 answers:
gogolik [260]3 years ago
8 0

Your answer should be 9.8 :)

iren2701 [21]3 years ago
4 0
The answer would be D: 9.8 m/s2
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3 0
3 years ago
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A 1300 kg car traveling at 35 mph rear-ends a 1000 kg car traveling 25 mph. Just after the collision (but before the driver’s sl
guajiro [1.7K]

Answer

given,

before collision

mass of car A = m_a = 1300 kg

velocity of car A = v_a  = 35 mph

mass of car B = m_b= 1000 kg

velocity of car B = v_b  = 25 mph

after collision

V_a = 30 mph

V_b = 31.5 mph

Initial momentum

P_1 = m_av_a + m_b v_b

P_1 = 1300 \times 35+ 1000 \times 25

P_1 =70500 Kg.m/s

final momentum

P_2 = m_aV_a + m_b V_b

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P_2 =70500 Kg.m/s

here  initial momentum is equal to the final momentum of the car.

hence, momentum is conserved in the collision.

6 0
3 years ago
Which chemical reaction is fastest
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3 0
3 years ago
What measures the amount of displacement in a transverse wave
MAVERICK [17]
Unlike a longitudinal wave, a transverse wave moves about, perpendicular to the direction of propagation. The particles in a transverse wave do not travel along the direction of propagation, but only oscillate up and down on its equilibrium position. With this, the displacement can be determined by measuring (in the case of electronic waves, using an oscilloscope or spectrum analyzer) and setting the desired units to measure the wave in.
4 0
3 years ago
Light of wavelength 500nm shines on a pair of slits. This produces an interference pattern on a screen 2.00m behind the slits. M
grandymaker [24]

Answer:

The  value is  d = 0.000125 \  m

Explanation:

From the question we are told that

   The  wavelength is  \lambda  =  500 \  nm =  500 *10^{-9 } \  m

    The  distance is of  the screen is  D =  2.0 \ m

    The  width of the fifth dark spot is y  =  4.00 \  cm  =  0.04 \  m

Generally the width of a fringe is mathematically represented as

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=>        0.04  =  \frac{ 5  * 500 *10^{-9}  *  2 }{d}

=>        d =  \frac{ 5  * 500 *10^{-9}  *  2 }{0.04}

=>        d = 0.000125 \  m

7 0
3 years ago
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