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DaniilM [7]
3 years ago
11

What is the perimeter of the triangle?​

Mathematics
2 answers:
Dmitrij [34]3 years ago
7 0

Answer:

19.24 cm

Step-by-step explanation:

Square the outsides of the triangle. 8 squared is 64 and 5 squared is 25.

A^2+B^2=C^2

c^2 is always the diagonal line.

a^2=25

c^2=64

Subtract 25 from 64 to find b^2

64-25= 39

Add all three together to get your perimeter.

The square root of 64 is 8, the square root of 25 is 5 and the square root of 39 is 6.24. Add 8, 5 and 6.24 together and you get the perimeter.

5+8+6.24= 19.24

irakobra [83]3 years ago
3 0

Step-by-step explanation:

As you can see , angle B = 72⁰ by angle sum property

So AB = AC = 8 cm (isosceles property)

Perimeter = 8 + 8 + 5 = 21 cm

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Step-by-step explanation:

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where the symbol \Phi (the uppercase greek alphabet phi) is the cumulative density function of the normal distribution, \mu is the mean and \sigma is the standard deviation of the normal distribution defined as N(\mu, \ \sigma).

According to the empirical rule stated above, the interval that contains the prices of 99.7% of college textbooks for a normal distribution N(113, \ 12),

                \Phi(113 \ - \ 3 \ \times \ 12 \ \leq \ X \ \leq \ 113 \ + \ 3 \ \times \ 12) \ = \ 0.9973 \\ \\ \\ \-\hspace{1.75cm} \Phi(113 \ - \ 36 \ \leq \ X \ \leq \ 113 \ + \ 36) \ = \ 0.9973 \\ \\ \\ \-\hspace{3.95cm} \Phi(77 \ \leq \ X \ \leq \ 149) \ = \ 0.9973

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