What is the perimeter of the triangle?
2 answers:
Answer:
19.24 cm
Step-by-step explanation:
Square the outsides of the triangle. 8 squared is 64 and 5 squared is 25.
A^2+B^2=C^2
c^2 is always the diagonal line.
a^2=25
c^2=64
Subtract 25 from 64 to find b^2
64-25= 39
Add all three together to get your perimeter.
The square root of 64 is 8, the square root of 25 is 5 and the square root of 39 is 6.24. Add 8, 5 and 6.24 together and you get the perimeter.
5+8+6.24= 19.24
Step-by-step explanation:
As you can see , angle B = 72⁰ by angle sum property
So AB = AC = 8 cm (isosceles property)
Perimeter = 8 + 8 + 5 = 21 cm
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