Question

ceiling with zero speed. Calculate the initial speed of the ball and the time it takes for it to reach the ceiling. A magician performs in a room with a ceiling, which is 2.70 m above his hands. He throws a ball upwards such that it reaches the ceiling with zero speed. Calculate the initial speed of the ball and the time it takes for it to reach the ceiling.

Answer 1

Answer:

a) v = 7.28 m/s

b) t = 0.74 s

Explanation:

a) The initial speed of the ball can be calculated using the following equation:

$V_{f}^{2} = V_{0}^{2} - 2gh$

Where:

$V_{f}$ is the final speed = 0

$V_{0}$ is the initial speed =?

g: is the gravity = 9.81 m/s²

h: is the height = 2.70 m

$V_{0} = \sqrt{2gh} = \sqrt{2*9.81 m/s^{2}*2.70 m} = 7.28 m/s$

Hence, the initial speed of the ball is 7.28 m/s.

b) To find the time that takes the balls to reach the ceiling we can use the next equation:

$V_{f} = V_{0} - gt$

$t = \frac{V_{0} - V_{f}}{g} = \frac{7.28 m/s}{9.81 m/s^{2}} = 0.74 s$

Therefore, the time it takes for the ball to reach the ceiling is 0.74 s.

I hope it helps you!