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2 years ago

6. Which does more wor:

Physics

1 answer:

umka2103 [35]2 years ago

8 0

Explanation:

1N=9,81 kg

1. 9,81×500×10=49.050

2. 9,81×100×40=39.240

option 1 does more wor

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Astronomers have recently observed stars orbiting at very high speeds around an unknown object near the center of our galaxy. Fo

nataly862011 [7]

Answer:

The mass of the object is 745000 units of the sun

Explanation:

We know that the centripetal force with which the stars orbit the object is represented as

$F_{c}$ = $\frac{mv^{2} }{r}$

and this centripetal force is also proportional to

$F_{c}$ = $\frac{kMm}{r^{2} }$

where

m is the mass of the stars

M is the mass of the object

v is the velocity of the stars = 10^6 m/s

r is the distance between the stars and the object = 10^14 m

k is the gravitational constant = 6.67 × 10^-11 m^3 kg^-1 s^-2

We can equate the two centripetal force equations to give

$\frac{mv^{2} }{r}$ = $\frac{kMm}{r^{2} }$

which reduces to

$v^{2}$ = $\frac{kM}{r}$

and then finally

M = $\frac{rv^{2} }{k}$

substituting values, we have

M = $\frac{10^{14}*(10^{6})^{2} }{6.67*10^{-11} }$ = 1.49 x 10^36 kg

If the mass of the sun is 2 x 10^30 kg

then, the mass of the the object in units of the mass of the sun is

==> (1.49 x 10^36)/(2 x 10^30) = 745000 units of sun

6 0

3 years ago

Develop expression for equation for uniform motion in a straight line

frozen [14]

According to cuneiform tablets in the ancient world, straight lines cannot cross, and no motion in the world is not relative. Btw...I KNOW!!! GOT MILK???

4 0

3 years ago

A cannon is mounted on a cart which sits on the ground, supported by frictionless wheels. The mass of the cannon and cart is 4.6

Kitty [74]

Answer:

The velocity of the launcher after the projectile is launched is -5.011 m/s

Explanation:

Here we have the mass of the cannon and cart, m₁ = 4.65 kg

Velocity of cannon and cart, v₁ = 2.00 m/s

Mass of projectile, m₂ = 50.0 g = 0.05 kg

Velocity of projectile, v₂ = 647 m/s

Velocity of the launcher, v₃ = Required

Mass of cannon and cart, launcher after launching projectile m₃ = 4.65-0.05

= 4.6 kg

Therefore, from the principle of the conservation of linear momentum, we have

Total initial momentum = Total final momentum

m₁ × v₁ = m₂ × v₂ + m₃ × v₃

Substituting gives

4.65 kg × 2.00 m/s = 0.05 kg × 647 m/s + 4.6 kg × v₃

4.65 kg × 2.00 m/s - 0.05 kg × 647 m/s = 4.6 kg × v₃

-23.05 kg·m/s = 4.6 kg × v₃

$v_3 = \frac{-23.05 \, kg\cdot m/s}{4.6 \, kg} = \frac{-461}{92} m/s$

v₃ = -5.011 m/s.

3 0

3 years ago

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What is true of all particles of gas enclosed within a container?

Andre45 [30]

Theyre all in constant motion

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3 years ago

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Which change occurs when an atom undergoes alpha decay?

oee [108]

In an alpha decay, an atom emits an alpha particle. An alpha particle consists of 2 protons and 2 neutrons: this means that during this kind of decay, the original atom loses 2 protons and 2 neutrons from its nucleus.

This also means that the atomic number Z of the element (the atomic number is the number of protons in the nucleus) decreases by 2 units in the process, while the mass number A (the mass number is the sum of the number of protons and neutrons) decreases by 4 units.

3 0

2 years ago

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