Helpp need answer for a test
1 answer:
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Answer:
Explanation:
Given that:-
Moles of K = 1.10 moles
Moles of Te = 0.55 moles
Moles of O = 1.65 moles
Taking the simplest ratio of the moles of the elements as:-
K : Te : O
1.10 : 0.55 : 1.65
2 : 1 : 3
Empirical formulas is the simplest or reduced ratio of the elements in the compound. So, the empirical formula is:-
Answer:
200 g C₆H₁₂O₆
General Formulas and Concepts:
<u>Chemistry - Solutions</u>
- Reading a Periodic Table
- Using Dimensional Analysis
- Molarity = moles of solute / liters of solution
Explanation:
<u>Step 1: Define</u>
1 M C₆H₁₂O₆
1 L of solution
<u>Step 2: Identify Conversions</u>
Molar Mass of C - 12.01 g/mol
Molar Mass of H - 1.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar mass of C₆H₁₂O₆ - 6(12.01) + 12(1.01) + 6(16.00) = 180.18 g/mol
<u>Step 3: Find moles of solute</u>
1 M C₆H₁₂O₆ = x mol C₆H₁₂O₆ / 1 L
x = 1 mol C₆H₁₂O₆
<u>Step 4: Convert</u>
<u /> = 180.18 g C₆H₁₂O₆
<u>Step 5: Check</u>
<em>We are given 1 sig figs. Follow sig fig rules and round.</em>
180.18 g C₆H₁₂O₆ ≈ 200 g C₆H₁₂O₆