The product in this chemical reaction is Carbon Dioxide or CO2.
This is because it states, "To form," which means that it was produced from the reactants Carbon and Oxygen.
To know what the products are in a statement rather than an equation, words such as produced and formed are used.
Hope this helps!
<u>Answer:</u> The standard free energy change of formation of
is 92.094 kJ/mol
<u>Explanation:</u>
We are given:
![K_{sp}\text{ of }Ag_2S=8\times 10^{-51}](https://tex.z-dn.net/?f=K_%7Bsp%7D%5Ctext%7B%20of%20%7DAg_2S%3D8%5Ctimes%2010%5E%7B-51%7D)
Relation between standard Gibbs free energy and equilibrium constant follows:
![\Delta G^o=-RT\ln K](https://tex.z-dn.net/?f=%5CDelta%20G%5Eo%3D-RT%5Cln%20K)
where,
= standard Gibbs free energy = ?
R = Gas constant = ![8.314J/K mol](https://tex.z-dn.net/?f=8.314J%2FK%20mol)
T = temperature = ![25^oC=[273+25]K=298K](https://tex.z-dn.net/?f=25%5EoC%3D%5B273%2B25%5DK%3D298K)
K = equilibrium constant or solubility product = ![8\times 10^{-51}](https://tex.z-dn.net/?f=8%5Ctimes%2010%5E%7B-51%7D)
Putting values in above equation, we get:
![\Delta G^o=-(8.314J/K.mol)\times 298K\times \ln (8\times 10^{-51})\\\\\Delta G^o=285793.9J/mol=285.794kJ](https://tex.z-dn.net/?f=%5CDelta%20G%5Eo%3D-%288.314J%2FK.mol%29%5Ctimes%20298K%5Ctimes%20%5Cln%20%288%5Ctimes%2010%5E%7B-51%7D%29%5C%5C%5C%5C%5CDelta%20G%5Eo%3D285793.9J%2Fmol%3D285.794kJ)
For the given chemical equation:
![Ag_2S(s)\rightleftharpoons 2Ag^+(aq.)+S^{2-}(aq.)](https://tex.z-dn.net/?f=Ag_2S%28s%29%5Crightleftharpoons%202Ag%5E%2B%28aq.%29%2BS%5E%7B2-%7D%28aq.%29)
The equation used to calculate Gibbs free change is of a reaction is:
![\Delta G^o_{rxn}=\sum [n\times \Delta G^o_f_{(product)}]-\sum [n\times \Delta G^o_f_{(reactant)}]](https://tex.z-dn.net/?f=%5CDelta%20G%5Eo_%7Brxn%7D%3D%5Csum%20%5Bn%5Ctimes%20%5CDelta%20G%5Eo_f_%7B%28product%29%7D%5D-%5Csum%20%5Bn%5Ctimes%20%5CDelta%20G%5Eo_f_%7B%28reactant%29%7D%5D)
The equation for the Gibbs free energy change of the above reaction is:
![\Delta G^o_{rxn}=[(2\times \Delta G^o_f_{(Ag^+(aq.))})+(1\times \Delta G^o_f_{(S^{2-}(aq.))})]-[(1\times \Delta G^o_f_{(Ag_2S(s))})]](https://tex.z-dn.net/?f=%5CDelta%20G%5Eo_%7Brxn%7D%3D%5B%282%5Ctimes%20%5CDelta%20G%5Eo_f_%7B%28Ag%5E%2B%28aq.%29%29%7D%29%2B%281%5Ctimes%20%5CDelta%20G%5Eo_f_%7B%28S%5E%7B2-%7D%28aq.%29%29%7D%29%5D-%5B%281%5Ctimes%20%5CDelta%20G%5Eo_f_%7B%28Ag_2S%28s%29%29%7D%29%5D)
We are given:
![\Delta G^o_f_{(Ag_2S(s))}=-39.5kJ/mol\\\Delta G^o_f_{(Ag^+(aq.))}=77.1kJ/mol\\\Delta G^o=285.794kJ](https://tex.z-dn.net/?f=%5CDelta%20G%5Eo_f_%7B%28Ag_2S%28s%29%29%7D%3D-39.5kJ%2Fmol%5C%5C%5CDelta%20G%5Eo_f_%7B%28Ag%5E%2B%28aq.%29%29%7D%3D77.1kJ%2Fmol%5C%5C%5CDelta%20G%5Eo%3D285.794kJ)
Putting values in above equation, we get:
![285.794=[(2\times 77.1)+(1\times \Delta G^o_f_{(S^{2-}(aq.))})]-[(1\times (-39.5))]\\\\\Delta G^o_f_{(S^{2-}(aq.))=92.094J/mol](https://tex.z-dn.net/?f=285.794%3D%5B%282%5Ctimes%2077.1%29%2B%281%5Ctimes%20%5CDelta%20G%5Eo_f_%7B%28S%5E%7B2-%7D%28aq.%29%29%7D%29%5D-%5B%281%5Ctimes%20%28-39.5%29%29%5D%5C%5C%5C%5C%5CDelta%20G%5Eo_f_%7B%28S%5E%7B2-%7D%28aq.%29%29%3D92.094J%2Fmol)
Hence, the standard free energy change of formation of
is 92.094 kJ/mol
B. Are produced only by living things
Anions are negative ions so it’s when an atom gains electrons
Answer: you will change the atom from one element to a different element. Sometimes, when you add a proton to an element, the element will become radioactive. If you change the number of neutrons in an atom, you get an isotope of the same element.
Explanation: