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Lynna [10]
3 years ago
7

What information does not need to be included a chemical waste label? Select one: Relative amounts of chemical compounds in the

container. The date the waste container was filled completely. A description of the experiment the chemicals were used for. Names of the chemical compounds present in the container.
Chemistry
1 answer:
Helga [31]3 years ago
5 0

Answer:

A description of the experiment the chemicals were used for.

Explanation:

A chemical waste label is required to provide information about any hazardous waste present in the container. Some details are mandatory to mention of the chemical waste label to prevent any accident while doing the experiment, that includes:

  • Chemical compound's name present in the container.
  • Composition and physical state of the waste.
  • Hazardous properties of the waste.
  • The date of manufacturing.
  • Amount of chemical compounds filled in the container.

A chemical waste label does not mention or describe the experiment for which the chemicals were used for, scientists, teacher or students should have knowledge of the chemical composition by reading their names and evaluate themselves on which chemical should be used for which experiment.

Hence, the correct answer is  "A description of the experiment the chemicals were used for."

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Answer:

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General Formulas and Concepts:

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

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<u>Stoichiometry</u>

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Explanation:

<u>Step 1: Define</u>

0.200 mol H₂S

<u>Step 2: Identify Conversions</u>

Molar Mass of H - 1.01 g/mol

Molar Mass of S - 32.07 g/mol

Molar Mass of H₂S - 2(1.01) + 32.07 = 34.09 g/mol

<u>Step 3: Convert</u>

  1. Set up:                    \displaystyle 0.200 \ mol \ H_2S(\frac{34.09 \ g \ H_2S}{1 \ mol \ H_2S})
  2. Multiply:                  \displaystyle 6.818 \ g \ H_2S

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

6.818 g H₂S ≈ 6.82 g H₂S

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