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3 years ago

Which is a chemical change?

Physics

2 answers:

statuscvo [17]3 years ago

8 0

Answer:

A. Splitting water into hydrogen and oxygen.

Explanation:

A chemical change produces a new substance. ... A physical change does not produce a new substance. Changes in state or phase (melting, freezing, vaporization, condensation, sublimation) are physical changes.

gladu [14]3 years ago

8 0

Splitting water into hydrogen and oxygen.

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Select the correct answer.

Vesna [10]

Answer:

Explanation:

Radiant= list onto solar panels, Electric= solar into power, Radiant= Electric into light

8 0

3 years ago

Read 2 more answers

A straight conductor carries a current of 755 A from east to west. It is 5.80 m above the ground. Part A Find the magnitude of t

Svetach [21]

Answer:

a. 2.6*10^{-5}T

b. north to south

Explanation:

In this case you have to take into account the expression for the magnetic field generated by a current

$B=\frac{\mu_0I}{2\pi r}$

where mu0 is the magnetic permeability of vacuum, I is the current and r is the distance to the conductor in which you want to measure the field.

A) By replacing we have

$B=\frac{(4\pi *10^{-7}\frac{T}{mA})(755A)}{2\pi (5.80m)}=2.6*10^{-5}T$

B) The direction is obtained by using the right hand rule. In this case, the current is from west to east. Then the direction is from north to south

Hope this helps!!

6 0

4 years ago

what is the amplitude and wavelength of the wave shown below? A. Amplitude: 15 cm; wavelength: 150 cm B. Amplitude: 30 cm; wavel

ehidna [41]

I would say C...............

5 0

4 years ago

Read 2 more answers

An archer shot a 0.06 kg arrow at a target. The arrow accelerated at 5,000 m/s2 to reach a speed of 50.0 m/s as it left the bow.

laila [671]

Answer:

300 N

Explanation:

The net force acting on the arrow is given by Newton's Second Law:

$F=ma$

where

m = 0.06 kg is the mass of the arrow

a = 5,000 m/s^2 is the acceleration of the arrow

Substituting the numbers into the equation, we find

$F=(0.06 kg)(5,000 m/s^2)=300 N$

7 0

4 years ago

A wire of resistance 5.9 Ω is connected to a battery whose emf ε is 4.0 V and whose internal resistance is 1.2 Ω. In 2.9 min, ho

dexar [7]

Answer:

a) 390J

b) 322J

c) 68J

Explanation:

We need to calculate the power given by the battery. the power is given by:

$P=V*I\\I=\frac{V}{R}\\I=\frac{4}{5.9+1.2}\\I=0.56A\\P=2.24W$

Watts is J/s so:

$E=P*t\\E=2.24\frac{J}{s}*2.9min*(60\frac{s}{min})=390J$

The thermal energy in the wire is given by:

$E_w=P_w*t\\P_w=I^2*R_w=0.56^2*5.9=1.85W\\E_w=1.85\frac{J}{s}*2.9min*(60\frac{s}{min})=322J$

And the the dissipated thermal energy in the battery will be the remainig energy:

$E_b=E-E_w\\E_b=390-322=68J$

4 0

4 years ago